Meaning of a simple preg_replace('!\s+!') pattern?

Asked Feb 24 '16 at 13:17

Active Feb 24 '16 at 13:17

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Sorry for the very basic question, but there's no easy way to search for a string like that. I have searched in PHP Manual (Pattern Syntax & preg_replace) but I haven't found any answers.

This code is inside a function that receives the $filter parameter. What does that preg_replace serves for?

$filter = preg_replace('!\s+!', ' ', $filter);

asked Feb 24 '16 at 13:17

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1

See: http://stackoverflow.com/q/22937618/3933332 – Rizier123 Feb 24 '16 at 13:19
It replaces all whitespace chunks with a single space. – Wiktor Stribiżew Feb 24 '16 at 13:21
Maybe exclamation point can sound strange: it is only a delimiter, you can change it with `/` or any other char not in pattern. `!\s+!` is the same as `/\s+/` – fusion3k Feb 24 '16 at 13:24

Meaning of a simple preg_replace('!\s+!') pattern?

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