Hello guys hope you can help me with this, becuase i have no idea... I want to upload an image into a database table i just need to upload the image, and some other data, right now i save all the info in the data base using the following Code:
$.ajax({
url: 'AccionesPHP.php',
type: 'POST',
data: {funcion:'SaveFamily',name:nam,lastn:ape,pasp:pas,dateb:dob,pased:ped,type:typ}
})
.done(function(datos)
{
if(datos==1)
{
alert('success');
}
});
and in the PHP side i have the following code:
case 'SaveFamily':
$nom = $_POST['name'];
$lastname = $_POST['lastn'];
$pasp = $_POST['pasp'];
$dateob = $_POST['dateb'];
$pexpd = $_POST['pased'];
$type = $_POST['type'];
$query= mysqli_query($link,"INSERT INTO ticketdatarecep VALUES(NULL,".$_SESSION['id_users'].", '$nom', '$lastname', '$pasp', '$dateob', '$pexpd', '$type')");
if($query == true)
{
echo "1";
}
else
{
echo mysql_error();
}
so i have no form in my HTML and i want to add an input so user can uoload an image and save it in the same table and everything, bu i have no clue how to do it, all i have seen use FORM to send the data but still dont know how to send the image using $.ajax and how to catch the image data in my PHP code.
Hope you can give me some ideas.