I want to implement such functionality in my simple Android app: when user visits a certain link (www.example.org let's say) in the web browser - Android OS should open my Android application if it is installed.
I tried to play with intent-filters like this:
<activity
android:name=".MainActivity"
android:label="@string/app_name"
android:theme="@style/AppTheme.NoActionBar">
<intent-filter>
<action android:name="android.intent.action.VIEW" />
<category android:name="android.intent.category.DEFAULT" />
<category android:name="android.intent.category.BROWSABLE" />
<data
android:host="example.org"
android:pathPattern="/.*"
android:scheme="http" />
<data
android:host="www.example.org"
android:pathPattern="/.*"
android:scheme="http"/>
</intent-filter>
<intent-filter>
<action android:name="android.intent.action.MAIN" />
<category android:name="android.intent.category.LAUNCHER" />
</intent-filter>
</activity>
But it's not working at all in google chrome mobile browser. In firefox, when I visit that link I get such Android icon on the right side of the search bar:
When I press that icon - my app opens. But still it is not what exactly I want to achieve.
Any idea why my code above doesn't work? I tried many variations of intent-filter declarations which I found on internet but nothing seem to work. I have nexus 5 device with Android 6 installed.