Can't understand this code

Question

I can't understand this code. please help me

function HelloFunc(func){
    this.greeting = "hello";
}

HelloFunc.prototype.call = function(func){
    func? func(this.greeting) : this.func(this.greeting);
}

var userFunc = function(greeting){
     console.log(greeting);
}

var objHello = new HelloFunc();
objHello.func = userFunc;
objHello.call();

func? func(this.greeting) : this.fun(this.greeting);

what's that mean?

also, I can't understand that code on the whole please explane that code

EEEck. Code should not attempt to override/replace the `fn.call()`. Make your own function name that doesn't conflict with built-in names. — jfriend00, Jan 24 '16 at 01:45

score 0 · Accepted Answer · answered Jan 24 '16 at 01:43

0

It's the ternary ?:-operator and can be rewritten as:

if (func) {
    func(this.greeting);
} else {
    this.func(this.greeting);
}

Only difference is, that the original expression has a value, but in the code snippet above it isn't used anyway.

answered Jan 24 '16 at 01:43

Ctx

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how does 'func' work in that code? – YankeeCki Jan 24 '16 at 01:52
`func` seems to be an optional parameter, which holds a function (which is a first-order value in javascript) when set. `if (func)` checks, if it was passed by the caller or not. In the first case, this function is called, in the latter case some default function is. – Ctx Jan 24 '16 at 01:54
thank you ! you're a hero – YankeeCki Jan 24 '16 at 01:59

Can't understand this code

1 Answers1