simple regular expression with equals but dont want to use split

Question

I have the message string as follows.

string=052

I need to use regular expression not split.

I want to return everything past the equals. 052 This is what i tried and gives me id=null

var regex = '[^?string=]';
var id2 = mystring.match(regex);

I have tried online regex checkers and it looks like it matches all but the a

is there a better reg ex i should try? id should not equal null.

You could perform a split on `=` or just do `message=[a-z0-9]+` — Mike Cluck, Jan 22 '16 at 19:31
I asked for regular expression not split. Split is not what i asked for. Please take it off duplicate. — , Jan 22 '16 at 21:13
This is a poor flagging, @WiktorStribiżew . It does not pertain to the OPs question directly. Expecting them to suss it out defeats the purpose of coming to SO for quick, distilled information. Either link to a better answer, or remove the flag. The OP specifically mentions not using split after an edit. Please remove this specific flagging and update appropriately. — kayleeFrye_onDeck, Jan 22 '16 at 21:48

score 1 · Accepted Answer · answered Jan 22 '16 at 19:33

1

You're using String.match() incorrectly. Try this:

var regex = '^message=(.*)$';
var id = queryString.match(regex)[1];

.match() returns an array; the first element (at [0]) is the entire matched string, and the second element (at [1]) is the part that's matched in the (first) set of parentheses in the regex.

answered Jan 22 '16 at 19:33

Blazemonger

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works as needed. Thank you – Jan 22 '16 at 21:11

simple regular expression with equals but dont want to use split

1 Answers1