accessing vector elements when passed using template

Question

I want to print the elements of the vector. The following is my code.

This is my code

After searching I found the following code and its working:

for(int i=0;i<vec.size();i++)
    cout<<vec[i]<<" ";

But can't we use iterators to access the elements? if possible, how?

instead of linking to an (external) image, please include the code in your question. — Sander De Dycker, Jan 21 '16 at 16:09
The error tells you what you need to do to fix it. You could also just use a [ranged based for loop](http://en.cppreference.com/w/cpp/language/range-for) — NathanOliver, Jan 21 '16 at 16:10

score 3 · Answer 1 · answered Jan 21 '16 at 16:11

3

typename is missing:

template <typename T>
void printArray(const std::vector<T>& a)
{
    for (typename std::vector<T>::const_iterator it = a.begin(); it != a.end(); ++it) {
        // ...
    }
}

In c++11, you may simply wrote:

template <typename T>
void printArray(const std::vector<T>& a)
{
    for (const auto& e : a) {
        std::cout << e << std::endl;;
    }
}

answered Jan 21 '16 at 16:11

Jarod42

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It might be helpful to say why typename is needed. Not saying you have to as the compiler told him why already. – NathanOliver Jan 21 '16 at 16:14
Oh dupe closing it would work. I keep forgetting about that one. – NathanOliver Jan 21 '16 at 16:16

score 0 · Answer 2 · answered Jan 21 '16 at 16:11

0

You can just do auto it = vec.begin() in case you're using C++11 so you don't really need to worry about the type of it.

answered Jan 21 '16 at 16:11

ForceBru

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In c++11, just use ranged for : (`for (const auto& e : a)`) – Jarod42 Jan 21 '16 at 16:14

accessing vector elements when passed using template

2 Answers2