Identifying which parameter is sent to the function

Asked Dec 21 '15 at 11:42

Active Dec 21 '15 at 11:43

Viewed 27 times

there is a function where the definition states 3 parameters.

ex:

function func(param1,param2,param3){
   //does somethings
}

I would like to call that same function with just providing the third parameter only. The solution I though of is the following.

func(undefined,undefined,valueForParam3);

I don't think this is the proper way to handle such a scenario. Providing that I've handled undefined in the function implementation where it sets defaults. Please guide me on this.

edited Dec 21 '15 at 11:43

thefourtheye

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asked Dec 21 '15 at 11:42

Imesh Chandrasiri

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"I don't think this is the propper way to handle such a scenario." — That **is** the proper way to handle it. – Quentin Dec 21 '15 at 11:43
Isn't setting undefined would confuse another developer is he's debugging? – Imesh Chandrasiri Dec 21 '15 at 11:44
1

If they can't handle idiomatic JS then that's their problem. – Quentin Dec 21 '15 at 11:45
If all parameters are optional, some may consider it better design to define only one parameter that receives an object. – Dec 21 '15 at 11:48

Identifying which parameter is sent to the function

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