Using ES2016 (ES7) Can I replace underscore's pick method?

Asked Dec 01 '15 at 03:04

Active Dec 01 '15 at 03:46

Viewed 79 times

The one thing I haven't figured out how to do using new ES syntax is create an object that is a subset of another based on declared included values.

Here's what I'm trying to do:

//input
let user = {
  id: 123,
  foo: 'foo',
  bar: 'bar',
  password: 'hunter2'
};

//output
let safeUser = {
  id: user.id,
  foo: user.foo,
  bar: user.bar
}

//NOT this (I don't want to declare excluded vals)
let {password, ...safeUser} = user;

If it's not possible, anyone know if something is in the works? I looked on esdiscuss & babel but nothing turned up.

asked Dec 01 '15 at 03:04

Matt K

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So you want to go from what's in `user` to what's in `safeUser`? That is, you want to include everything but (in this case) `password`? – Hawken MacKay Rives Dec 01 '15 at 03:07
yep! but without excluding `password`. – Matt K Dec 01 '15 at 03:09
wait – so, if you don't want to exclude `password`, what are you trying to do? What do you want in the final object that's different from the other two? – Hawken MacKay Rives Dec 01 '15 at 03:12
I don't want to *exclude* `password`, I want to declaratively *include* everything else. It's the difference between `_.pick()` and `_.omit()` – Matt K Dec 01 '15 at 03:14
I'm sorry to ask this of you, but could you write out an equivalent `_.pick` expression for me, please? – Hawken MacKay Rives Dec 01 '15 at 03:23
`_.pick(user, 'id', 'foo', 'bar')` – Matt K Dec 01 '15 at 03:24
http://underscorejs.org/#pick – Saad Dec 01 '15 at 03:27

Using ES2016 (ES7) Can I replace underscore's pick method?

0 Answers0