Regular expression for match 8 numbers starting with 40|41|43

Question

I'm trying to build a regular expression to match exactly this kind of format:

40XXXXXX 41XXXXXX 43XXXXXX

So far i have this \d{2}(^40?|^41?|^43?)\d{6}

But it doesn't work, i've spend hours in http://regexr.com/ trying to make it work without luck

Appreciate your help

I don't understand why you used `\d{2}` at the beginning of your regex. Also, you need to match `$` the end of string. `^4[013]\d{6}$` — Mariano, Nov 19 '15 at 10:28
Possible duplicate of [Reference - What does this regex mean?](http://stackoverflow.com/questions/22937618/reference-what-does-this-regex-mean) — Mariano, Nov 19 '15 at 10:30

Tushar · Accepted Answer · 2015-11-19T10:31:15.040

2

Use following regex

/^4(0|1|3)[0-9]{6}$/

Or,

/^4[013][0-9]{6}$/

Explanation:

edited Nov 19 '15 at 10:31

answered Nov 19 '15 at 10:26

Tushar

1

Thanks! You my friend are a life saviour! – Douglas Roos Nov 19 '15 at 10:28
2

You still can use `[013]` instead of `(0|1|3)`. – Wiktor Stribiżew Nov 19 '15 at 10:30

1 Answers1