I'm confused about this php get code

Question

$check=$$_GET[u];

if($_GET[user] && $_GET[user]==$check)

I don't under stand about $check=$$_GET[u]; Why that used double $ ?? so what is value of $check u guess?

[variable variables](http://php.net/manual/en/language.variables.variable.php) See the **big red warning** at the bottom of the page — Rizier123, Oct 19 '15 at 10:53
Please check http://stackoverflow.com/questions/4179489/double-dollar-sign-php — mario.klump, Oct 19 '15 at 10:53
suppose $_GET['u'] value is xxx;then $check value is equal to $xxx — ManiMuthuPandi, Oct 19 '15 at 10:54

score 0 · Answer 1 · answered Oct 19 '15 at 11:07

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It takes the value of one variable and treats it as name of second variable.

Variable variables This can help you in understanding it with an example.

answered Oct 19 '15 at 11:07

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score 0 · Accepted Answer · answered Oct 19 '15 at 11:24

The double $ makes a variable with a name equal to the value of the original variable. Example

$name = "steve";

$$name = "jobs";

print ($steve); // The output is: jobs

What we've done is that we made a new variable, and the new variables name was the value of $name. We assigned "jobs" to the variable by the name of $name's value.

I'm confused about this php get code

2 Answers2