Why does this switch statement not work?

Question

import java.util.Scanner;

public class VerticalWire {
    public static void main(String[] args)
    {  
        Scanner in = new Scanner(System.in);
        System.out.println("how many wires");
        String howManyWires = in.next();

        switch(howManyWires) {
            case "3":
            {
                 System.out.println("true");
                 break;
            }

            case "3 5":
            {
                 System.out.println("false");break;}
            }
     }
}

I tested if I enter "3 5" it returns true even though I think it should return false! What is wrong?

Have a read of what [`Scanner#next`](https://docs.oracle.com/javase/8/docs/api/java/util/Scanner.html#next--) actually does, then use `Scanner#nextLine` instead — MadProgrammer, Oct 15 '15 at 04:56

Naman Gala · Answer 1 · 2015-10-15T05:05:15.290

0

Use in.nextLine() instead of in.next().

Documentation of scanner.next() states that

Finds and returns the next complete token from this scanner.

So when you enter 3 5 as input, it will read only 3 when you call next method and if you again call next method then it will read 5.

edited Oct 15 '15 at 05:05

answered Oct 15 '15 at 04:56

Naman Gala

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Why should they? (I know the answer, but you need to tell the OP ;)) – MadProgrammer Oct 15 '15 at 04:57
@MadProgrammer - You don't have to say - *I know the answer*. We know you know :P – TheLostMind Oct 15 '15 at 05:01
1

@TheLostMind People often mistaken me for the OP ;) – MadProgrammer Oct 15 '15 at 05:04
@MadProgrammer - If only they knew how to hover the mouse over a person's name :) – TheLostMind Oct 15 '15 at 05:18

Why does this switch statement not work?

1 Answers1