how to read int,double,and sentence of string using same scanner variable

Question

import java.util.Scanner;

public class Solution {

    public static void main(String[] args) {
            Scanner sc=new Scanner(System.in);
            String s=new String();
            int x=sc.nextInt();
            double y=sc.nextDouble();
            s = sc.next();

            System.out.println("String:"+s);
            System.out.println("Double: "+y); 
            System.out.println("Int: "+x);     
     }       
}

it scans only one word pleasd give any suggestions...

@FastSnail and keppil I dont think its a dupe OP is not using `nextLine()` anywhere — singhakash, Oct 05 '15 at 12:24
`next()` only reads one word, this is it's purpose. If you want to read a whole line use `nextLine();` — Peter Lawrey, Oct 05 '15 at 12:26
@PeterLawrey can you reopen the question as it is not a dupe of the given thread? — singhakash, Oct 05 '15 at 13:01
@Fastsnail: I figured it was close enough, and had an accepted answer that explained and resolved the situation here as well. Good thing you got it reopened since multiple people didn't agree with me though. — Keppil, Oct 05 '15 at 13:14

score 20 · Answer 1 · edited Dec 04 '17 at 10:35

You can try this code:

import java.util.Scanner;

public class Solution {

public static void main(String[] args) {
    Scanner scan = new Scanner(System.in);
    int i = scan.nextInt();
    double d = scan.nextDouble();

    scan.nextLine();
    String s = scan.nextLine();

    System.out.println("String: " + s);
    System.out.println("Double: " + d);
    System.out.println("Int: " + i);
}

Because the Scanner object will read the rest of the line where its previous read left off.

If there is nothing on the line, it simply consumes the newline and moves to the starting of the next line.

After double declaration, you have to write: scan.nextLine();

score 6 · Answer 2 · edited May 23 '17 at 12:34

6

s = sc.next();

it scans only one word pleasd give any suggestions...

This is what next(); is intended to do. If you want to read multiple words, the simplest solution is to read a line of text. e.g.

String s = sc.nextLine();

If you need to read multi-line text, you need to workout a strategy for doing this such as reading everything in a loop until you have a blank line.

Note: while the answer is similar to Scanner is skipping nextLine() after using next(), nextInt() or other nextFoo() methods the difference is that you don't discard the rest of the line, but rather you use the String returned by nextLine();

If you are expecting the input to be

 1 2.0 Hello World

then you want to use the suggestion above, however if the input is on multiple lines like this

 1 2.0
 Hello World

You will need to discard the rest of the line with an extra class to nextLine() as the link above suggests.

edited May 23 '17 at 12:34

Community

1
1

answered Oct 05 '15 at 13:04

Peter Lawrey

498,481
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700
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Well, since you're one of those who removed the dupe note of [this question](http://stackoverflow.com/questions/13102045/skipping-nextline-after-using-next-nextint-or-other-nextfoo-methods), you could add a note to your answer to avoid a following question with exactly this problem :). If the uses `nextLine` instead, then his input will be skipped. – Tom Oct 05 '15 at 13:19
@Tom Thank you, I have added a comment as to why it is similar but not a dup. – Peter Lawrey Oct 05 '15 at 13:22
That's not what I meant :P. It is currently not a dupe, correct, but since you suggest to use `nextLine` instead of `next` to read the whole line, he will run into the same problem asked in that question. His new `nextLine` call will read the rest of the line, that was left behind of the prior `nextDouble()` call. With "the note you could write" I meant that you can lead him to that question to get this problem solved when he runs into it. – Tom Oct 05 '15 at 13:30
1

@Tom You could be right, it's not clear from the OP's question whether the String is on the same line as I assumed or on a different line. – Peter Lawrey Oct 05 '15 at 13:57
1

Right, this could be true ... never thought about an input like "1 1.0 test blub test" (on the same line). – Tom Oct 05 '15 at 13:58
1

@Tom worth adding a note about each possibility. Thank you. – Peter Lawrey Oct 05 '15 at 14:00

score 6 · Answer 3 · edited Apr 08 '16 at 07:49

import java.util.Scanner;

public class Solution {

    public static void main(String[] args) {
        Scanner sc = new Scanner(System.in);
        int x = sc.nextInt();
        double y = sc.nextDouble();
        sc.nextLine();
        String s = sc.nextLine();

        System.out.println("String: " + s);
        System.out.println("Double: " + y);
        System.out.println("Int: " + x);
    }
}

score 3 · Answer 4 · answered Feb 13 '19 at 02:33

Why don't you skip as follows

import java.util.Scanner;

public class Solution {

public static void main(String[] args) {
    Scanner scan = new Scanner(System.in);
    int i = scan.nextInt();
    scanner.skip("(\r\n|[\n\r\u2028\u2029\u0085])?");
    double d = scan.nextDouble();
    scanner.skip("(\r\n|[\n\r\u2028\u2029\u0085])?");

    scan.nextLine();
    String s = scan.nextLine();

    System.out.println("String: " + s);
    System.out.println("Double: " + d);
    System.out.println("Int: " + i);
}

score 0 · Answer 5 · answered Feb 15 '17 at 17:01

I'd rather suggest to try out this block of code

Scanner scan = new Scanner();
int i = Integer.parseInt(scan.nextLine());
double d = Double.parseDouble(scan.nextLine());
String s = scan.nextLine();

I hope this would not skip reading the String input (or just read a single word skipping rest of the Line) after a double or integer input..

follow me on fb/ayur.sharma

score 0 · Answer 6 · answered Apr 06 '17 at 12:26

If you use the nextLine() method immediately following the nextInt() method, recall that nextInt() reads integer tokens; because of this, the last newline character for that line of integer input is still queued in the input buffer and the next nextLine() will be reading the remainder of the integer line (which is empty).

score 0 · Answer 7 · answered Oct 06 '17 at 17:06

0

import java.util.Scanner;

public class Solution 
{
    public static void main(String[] args) 
    {
     Scanner scan = new Scanner(System.in);
     int i = Integer.parseInt(scan.nextLine());
     double d = Double.parseDouble(scan.nextLine());
     String s = scan.nextLine();

     System.out.println("String: " + s);
     System.out.println("Double: " + d);
     System.out.println("Int: "+ i);
     }
}

answered Oct 06 '17 at 17:06

Sneha

1
1

Take input - int, double and sentence. print the same as output – Sneha Oct 06 '17 at 17:08
This doesn't work for all valid reasons! You have to check Arun's answer for the working solution! – N00b Pr0grammer Jan 12 '20 at 04:56

score 0 · Answer 8 · answered Nov 05 '17 at 02:39

import java.util.Scanner;

public class Solution 
{
    public static void main(String[] args) 
    {
     Scanner scan = new Scanner(System.in);
     int i = Integer.parseInt(scan.nextLine());
     double d = Double.parseDouble(scan.nextLine());
     scan.nextLine();
     String s = scan.nextLine();
     scan.close();

     System.out.println("String: " + s);
     System.out.println("Double: " + d);
     System.out.println("Int: "+ i);
     }
}

When switching between reading tokens of input and reading a full line of input, you need to make another call to nextLine() because the Scanner object will read the rest of the line where its previous read left off.

If there is nothing on the line, it simply consumes the newline and moves to the beginning of the next line.

After double declaration, you have to write: scan.nextLine();

score 0 · Answer 9 · answered Apr 12 '20 at 21:22

Here is your answer

public static void main(String[] args) {     
    Scanner scan = new Scanner(System.in);

    int i = scan.nextInt();         
    double d = scan.nextDouble(); 

    scan.nextLine();
    String s = scan.nextLine();  

    //if you want to skip the unnecessary input
    //scanner.skip("(\r\n|[\n\r\u2028\u2029\u0085])?");

    System.out.println("String: " + s);       
    System.out.println("Double: " + d);      
    System.out.println("Int: " + i);

   scan.close();
}

how to read int,double,and sentence of string using same scanner variable

9 Answers9