System.out.println not working for string

Question

I'm trying to learn Java through Hackerrank and the challenge that I'm working on currently takes an int, double, and string and prints them on separate lines in reverse order, but I haven't been able to get the string to print.

import java.util.Scanner;

public class Solution {

    public static void main(String[] args) {
            Scanner sc=new Scanner(System.in);
            int x=sc.nextInt();
            double y=sc.nextDouble();
            String s=sc.nextLine();

            System.out.println("String: "+s);
            System.out.println("Double: "+y);
            System.out.println("Int: "+x);
         }
    }

The input is:

42
3.1415
Welcome to Hackerrank Java tutorials!

And output is:

String:
Double: 3.1415
Int: 42

I don't know Java at all, but from the code I've seen online, I can't tell why this is wrong.

Related answer: http://stackoverflow.com/questions/19077908/beginner-trying-to-program-a-simple-calculator/19077970#19077970 — Nayuki, Sep 20 '15 at 22:30
Related answer: http://stackoverflow.com/questions/18163518/while-loop-executes-only-once/18163608#18163608 — Nayuki, Sep 20 '15 at 22:31

score 2 · Accepted Answer · answered Sep 20 '15 at 22:28

2

Change the first part of the code to this:

        Scanner sc = new Scanner(System.in);
        int x = sc.nextInt();
        double y = sc.nextDouble();
        sc.nextLine();  // Discard rest of current line
        String s = sc.nextLine();

The way java.util.Scanner splits the input into numbers or lines is a bit weird.

answered Sep 20 '15 at 22:28

Nayuki

16,655
5
47
75

It works! Why is that only necessary for the string and not the others? – Xochozomatli Sep 20 '15 at 22:34

Beryllium · Answer 2 · 2015-09-20T22:35:03.457

-1

The sc.nextLine(); should instead be sc.next();

edited Sep 20 '15 at 22:35

answered Sep 20 '15 at 22:27

Beryllium

546
7
19

There is no `nextln()`, and `next()` does not solve the problem. – Nayuki Sep 20 '15 at 22:32
.next() works fine for what they are trying to do. It will return the next token entered as a String. – Beryllium Sep 20 '15 at 22:37
What if the string line contains spaces? – Nayuki Sep 20 '15 at 22:49

System.out.println not working for string

2 Answers2