Php return jpg as content for tag

Question

I want to return jpg image on some url in my app (example.com/my/url/to/image).

function footer_image(){

    $name = "/assets/img/mail.jpg";

    header("Content-Type: image/jpg", TRUE);
    header("Content-Length: " . filesize($name));
    echo file_get_contents($name);
}

And I got only broken image :( Tried also this:

   // open the file in a binary mode
$name = "/assets/img/mail.jpg";
$fp = fopen($name, 'rb');

// send the right headers
header("Content-Type: image/jpg");
header("Content-Length: " . filesize($name));

// dump the picture and stop the script
fpassthru($fp);
exit;

When i var_dump $fp I get it's content. Looks like I have bad headers set.

possible duplicate of [Output an Image in PHP](http://stackoverflow.com/questions/1851849/output-an-image-in-php) — FuzzyTree, Sep 08 '15 at 12:43
What do you mean by "broken image"? Also try to set the header to `image/jpeg` — KhorneHoly, Sep 08 '15 at 12:44
@FuzzyTree Tried solution from your link and nothing, still no output — Blejwi, Sep 08 '15 at 13:31
@KhorneHoly There is icon of img, the same icon when src is invalid — Blejwi, Sep 08 '15 at 13:32
Suggestion: create a hyperlink to the image, right click on it and save the image to disk. Open the image in a hex editor (hexedit.com) and check that the file has a valid JPEG header. — Isometric, Sep 08 '15 at 13:49
PHP 5.2, kohana 2 it's a very old project but I have to fix some issuses in it. — Blejwi, Sep 09 '15 at 06:21
@RichardBrock No matter what image I use, always the same problem — Blejwi, Sep 09 '15 at 08:18

score 0 · Answer 1 · edited May 23 '17 at 10:26

0

Use Content/type: image/jpeg instead of image/jpg

For automation header Content type set you can use this:

$file_extension = strtolower(substr(strrchr($filename,"."),1));

switch( $file_extension ) {
    case "gif": $ctype="image/gif"; break;
    case "png": $ctype="image/png"; break;
    case "jpeg":
    case "jpg": $ctype="image/jpeg"; break;
    default:
}

header('Content-type: ' . $ctype);

https://stackoverflow.com/a/2634072/4015178

edited May 23 '17 at 10:26

Community

1
1

answered Sep 08 '15 at 12:53

Raimondas Kazlauskas

239
1
11

@Blejwi Are you set a header in the document start? – Raimondas Kazlauskas Sep 09 '15 at 06:28
Just before echo content:`$img = file_get_contents($name); header('Content-Type: image/jpeg', TRUE); echo $img;` – Blejwi Sep 09 '15 at 06:31
File does not have additionals headers from includes? It's plain PHP? – Raimondas Kazlauskas Sep 09 '15 at 06:33
It's old project built on kohana 2 – Blejwi Sep 09 '15 at 06:37
You can check if headers are set: var_dump(headers_sent()); – Raimondas Kazlauskas Sep 09 '15 at 06:54
Got false. (Had to comment jpeg header because I couldnt see it) – Blejwi Sep 09 '15 at 07:12

score 0 · Answer 2 · edited Oct 23 '17 at 07:30

If the image is really the type JPG. Should work with: Content-type: image/jpeg and NOT with Content-type: image/jpg

To automatically check the Content-type, you could use the code below:

function footer_image() {
    $name = "/assets/img/mail.jpg";
    $finfo = finfo_open(FILEINFO_MIME_TYPE); 
    $mime = finfo_file($finfo, $name) ; // return the mimetype 
    header("Content-Type: " . $mime, TRUE);
    header("Content-Length: " . filesize($name));
    echo file_get_contents($name);
}

You could try this in PHP 5.2 or 5.3:

function footer_image() {
    $name = "/assets/img/mail.jpg";
    $mime = mime_content_type($name) ; // php 5.2 and 5.3 = return the mimetype 
    header("Content-Type: " . $mime); // remove the ', true'
    // header("Content-Length: " . filesize($name)); // remove this line to test
    echo file_get_contents($name);
}

Php return jpg as content for tag

2 Answers2