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I am trying to send a text and a image via HTTP POST and I always get a 400 error. I would like to use it to send a image via Telegram bot and I am using the code provided in this answer with a text and bite parameters https://stackoverflow.com/a/2793153/1970613 with small modifications.

What could be the error? Many thanks in advanced!

                    String param  = "chat_id=mi_id&photo=";
                    String charset = "UTF-8"; 
                    String request = "https://api.telegram.org/bot-botCOde/sendPhoto";
                    URL url = new URL( request );
                    File binaryFile = new File("/home/joseantonio/imagen.jpg");
                    String CRLF = "\r\n"; // Line separator required by multipart/form-data.
                    String boundary = Long.toHexString(System.currentTimeMillis());

                    HttpURLConnection conn= (HttpURLConnection) url.openConnection();           
                    conn.setDoOutput( true );
                    conn.setInstanceFollowRedirects( false );
                    conn.setRequestMethod( "POST" );
                    conn.setRequestProperty( "charset", "utf-8");
                    conn.setRequestProperty("Content-Type", "multipart/form-data; boundary=" + boundary);
                        conn.setUseCaches( false );
                    try{ 
                         OutputStream output = conn.getOutputStream();
                         PrintWriter writer = new PrintWriter(new OutputStreamWriter(output, charset), true);

                         writer.append("--" + boundary).append(CRLF);
                         writer.append("Content-Disposition: form-data; name=\"param\"").append(CRLF);
                         writer.append("Content-Type: text/plain; charset=" + charset).append(CRLF);
                         writer.append(CRLF).append(param).append(CRLF).flush();

                         writer.append("--" + boundary).append(CRLF);
                         writer.append("Content-Disposition: form-data; name=\"binaryFile\"; filename=\"" + binaryFile.getName() + "\"").append(CRLF);
                         writer.append("Content-Type: image/jpg").append(CRLF);
                         writer.append("Content-Transfer-Encoding: binary").append(CRLF);
                         writer.append(CRLF).flush();                            
                         Files.copy(binaryFile.toPath(), output);
                         output.flush(); // Important before continuing with writer!
                         writer.append(CRLF).flush(); // CRLF is important! It indicates end of boundary.

                         // End of multipart/form-data.
                         writer.append("--" + boundary + "--").append(CRLF).flush();

                        int responseCode2 = conn.getResponseCode();

                        System.out.println("\nSending 'GET' request to URL : " + request);
                        System.out.println("Response Code : " + responseCode2);
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Jose A Lopez Pastor
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1 Answers1

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I believe the fact that you are using https url is the cause of the error you are getting. You need to handle things a little different when you are submitting to an https url. See an example here

chrisl08
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