single decimal precision in java

Question

I have a double such as 32.559.

How would I get rid of all but one decimal digit so my output would look like 32.5?

The lack of own research will probably lead to a lot downvotes ... You should add what you have tried and why it did not meet your requirements. — Fildor, Sep 01 '15 at 14:19
Please at least make some research effort next time. A google search with your *exact* title copy and pasted reveals this obvious duplicate: [How to round a number to n decimal places in Java](http://stackoverflow.com/questions/153724/how-to-round-a-number-to-n-decimal-places-in-java) — tnw, Sep 01 '15 at 14:27

score 0 · Answer 1 · answered Sep 01 '15 at 14:16

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float f = 32.559f;
System.out.printf("%.1f", f);

answered Sep 01 '15 at 14:16

James Wierzba

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score 0 · Answer 2 · answered Sep 01 '15 at 14:18

0

I'm assuming you just want to print it that way:

String result = String.format("%.1f", value);

answered Sep 01 '15 at 14:18

DarkDust

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score 0 · Answer 3 · edited Sep 01 '15 at 14:58

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You can use DecimalFormat:

Locale locale  = new Locale("en", "UK");
String pattern = "###.#";

DecimalFormat decimalFormat = (DecimalFormat)
NumberFormat.getNumberInstance(locale);
decimalFormat.applyPattern(pattern);

String format = decimalFormat.format(32.559);
System.out.println(format);

The output printed from this code would be:

32.5

This is the Basic above, you can go throws here for more details.

edited Sep 01 '15 at 14:58

Francisco Romero

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answered Sep 01 '15 at 14:18

Janny

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Won't it round it up to print `32.6`? – RobAu Sep 01 '15 at 14:19
1

This outputs 32.6 for me – James Wierzba Sep 01 '15 at 14:45

single decimal precision in java

3 Answers3