How to get params in url , and it is array? yii2

Question

I have url like this

 http://localhost/belajar4/web/index.php?r=data%2Fsingle&id=2&DataSearch[TANGGAL]=2015-08-04&DataSearch[TANGGAL_SELESAI]=2015-08-12

And I want to get DataSearch['Tanggal'] dan DataSearch[TANGGAL_SELESAI]

I have tried for id with

 Yii::$app->request->queryParams['id']

And it was success for it, but not with DataSearch['Tanggal']

When I try for DataSearch['Tanggal'] the error is

 Undefined index: DataSearch[TANGGAL]

I think it should have easy to answer but i am newbie for yii2 and i didnt find the solution yet

oh ya thats work, i got the array. but what i need is the string DataSearch['TANGGAL'] and DataSearch['TANGGAL_SELESAI'] separated. — Noobs To be Pro Addict, Aug 15 '15 at 06:07
array(2) { ["TANGGAL"]=> string(10) "2015-08-04" ["TANGGAL_SELESAI"]=> string(10) "2015-08-12" } — Noobs To be Pro Addict, Aug 15 '15 at 06:07
it is just array. So you can access it as each other array. See my answer. — Jakuje, Aug 15 '15 at 06:08

score 6 · Accepted Answer · answered Aug 15 '15 at 06:08

6

You can get them from array like this:

Yii::$app->request->queryParams['DataSearch']["TANGGAL_SELESAI"]
Yii::$app->request->queryParams['DataSearch']["TANGGAL"]

answered Aug 15 '15 at 06:08

Jakuje

score 2 · Answer 2 · answered Aug 15 '15 at 14:54

You can also use combination of ArrayHelper::getValue() and Yii::$app->request->get() with dot notation:

use Yii;
use yii\helpers\ArrayHelper;


...

$value = ArrayHelper::getValue(Yii::$app->request->get(), 'DataSearch.TANGGAL_SELESAI');

The main advandage is you can avoid Undefined index exception and change default value (third parameter).

Official docs:

score -1 · Answer 3 · answered Jan 06 '20 at 04:43

I had faced slimier issue & spent lots of time to get the value but somehow I found solution like below.

// Trying to print the value

echo Yii::$app->request->queryParams['DataSearch']['"TANGGAL_SELESAI"'];

echo Yii::$app->request->queryParams['DataSearch']['"TANGGAL"'];

3 Answers3