I have a number of .csv files in a folder (1.csv, 2.csv, 3.csv, etc.) and I need to loop over them all. The output should be a corresponding NEW file for each existing one, but each should only contain 2 columns.
Here is a sample of the csv files:
004,444.444.444.444,448,11:16 PDT,11-24-15
004,444.444.444.444,107,09:55 PDT,11-25-15
004,444.444.444.444,235,09:45 PDT,11-26-15
004,444.444.444.444,241,11:00 PDT,11-27-15
And here is how I would like the output to look:
448,11-24-15
107,11-25-15
235,11-26-15
241,11-27-15
Here is my working attempt at achieving this with Python:
import csv
import os
import glob
path = '/csvs/'
for infile in glob.glob( os.path.join(path, '*csv') ):
inputfile = open(infile, 'r')
output = os.rename(inputfile + ".out", 'w')
#Extracts the important columns from the .csv into a new file
with open(infile, 'r') as source:
readr = csv.reader(source)
with open(output,"w") as result:
writr = csv.writer(result)
for r in readr:
writr.writerow((r[4], r[2]))
Using only the second half of this code, I am able to get the desired output by specifying the input files in the code. However, this Python script will be a small part of a much larger bash script that will be (hopefully) fully automated.
How can I adjust the input of this script to loop over each file and create a new one with just the 2 specified columns?
Please let me know if there is anything I need to clarify.