extract start and end date with regex group

Question

I have a service period mentioned as

MAY 01-15

and I need to extract start and end date as

group 1 : MAY 01
group 2 : MAY 15

is it possible???

java...but my framework permits only limited operation.I cant use much of core java — Santhosh Thamaraiselvan, Jul 13 '15 at 10:21
Could you provide your attempt to solve the problem in the question? — Jonny 5, Jul 13 '15 at 11:04

score 0 · Answer 1 · answered Jul 13 '15 at 10:36

0

It is possible.

This Expression

@(Jan|Feb|May) (\d{1,2})-(\d{1,2})@is

gives you the following Array

Array
(
    [0] => May 01-15
    [1] => May
    [2] => 01
    [3] => 15
)

You should expand the first parenthesis with all the months you need/want.

answered Jul 13 '15 at 10:36

Dennis Christian

166
2
14

Then you need to break the string into particles and match these manually. – Dennis Christian Jul 13 '15 at 10:45

score 0 · Answer 2 · edited May 23 '17 at 12:25

How about using Java - String replaceAll() Method? Assuming your input is like sample.

String str = "MAY 01-15";

String start = str.replaceAll("-\\d+$", "");
System.out.println(start);

MAY 01

String end = str.replaceAll("\\b\\d+-", "");
System.out.println(end);

MAY 15

See test at ideone.com; Regex test at regexplanet (click on "Java")

$ is the end anchor
\d is a short for [0-9]
+ quantifier for 1 or more
\b matches a word boundary

Also see SO regex faq

If the sample is only a fragment, first extract the relevant part:

String full_str = "foo bar MAY 01-15 Lorem ipsum dolor sit amet, consetetur, adipisci velit";
String str = full_str.replaceAll("(?s)^.*?(\\b[A-Z]{3,}\\s+\\d{2}-\\d{2})(?!-).*", "$1");

Explanation at regex101 (top right)

extract start and end date with regex group

2 Answers2