java : create string objects using a delimeter

Question

I have input string array containing value like

1950/00/00;1953/00/00;1958/00/00;1960/00/00;1962/0

What could be the best way to obtain values out of above input which contains 1950/00/00, 1953/00/00, 1958/00/00 , 1960/00/00 and 1962/0 in individual string objects?

Use the method [`String.split(regex)`](http://docs.oracle.com/javase/8/docs/api/java/lang/String.html#split-java.lang.String-) — Jesper, Jun 16 '15 at 07:52
You can use either `StringTokenizer` or `String.split` method http://stackoverflow.com/a/691224/2445298. Comparison is given in that link — Krishanthy Mohanachandran, Jun 16 '15 at 07:57

score 2 · Accepted Answer · answered Jun 16 '15 at 07:54

2

Use the method String.split(regex):

String input = "1950/00/00;1953/00/00;1958/00/00;1960/00/00;1962/0";

String[] parts = input.split(";");

for (String part : parts) {
    System.out.println(part);
}

answered Jun 16 '15 at 07:54

Jesper

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score 1 · Answer 2 · 2015-06-16T08:03:48.020

1

The split() method splits the string based on the given regular expression or delimiter, and returns the tokens in the form of array. Below example shows splitting string with (;)

public class MyStrSplit {

    public static void main(String a[]){

        String str = "1950/00/00;1953/00/00;1958/00/00;1960/00/00;1962/0";
        String[] tokens = str.split(";");
        for(String s:tokens){
            System.out.println(s);
        }
    }
}

edited Jun 16 '15 at 08:03

answered Jun 16 '15 at 07:56

Could you please elaborate more your answer adding a little more description about the solution you provide? – abarisone Jun 16 '15 at 07:58
The split() method splits the string based on the given regular expression or delimiter, and returns the tokens in the form of array – Jun 16 '15 at 08:04

score 0 · Answer 3 · answered Jun 16 '15 at 08:57

Another choice to split string by regular expression:

public class SpitByRegx
{
  public static void main(String[] args)
  {
    String input = "1950/00/00;1953/00/00;1958/00/00;1960/00/00;1962/0";

    Pattern pattern = Pattern.compile("([0-9/]+);?");

    Matcher m = pattern.matcher(input);

    while(m.find())
    {
        System.out.println(m.group(1));
    }
  }
}

java : create string objects using a delimeter

3 Answers3