remove localstorage array object base on value

Question

Says I have this saved key in my localstorage, how to remove the player_id that has value of 2 and shoe size_of 1?

[{"player_id":1,"shoe_size":3},{"player_id":2,"shoe_size":1},{"player_id":2,"shoe_size":2},

What to do next after I get the saved value?

if(localStorage["player"]){
    player = JSON.parse(localStorage["player"]);
}

Satpal · Answer 1 · 2015-06-01T08:20:44.587

1

You can use .filter()

The filter() method creates a new array with all elements that pass the test implemented by the provided function.

player  = player .filter(function( obj ) {
    return !(obj.player_id == 2 && obj.shoe_size == 1);
});

If you want to set it:

localStorage["player"] = JSON.stringify(player)

var player = [{"player_id":1,"shoe_size":3},{"player_id":2,"shoe_size":1},{"player_id":2,"shoe_size":2}];

player  = player.filter(function(obj) {
    return !(obj.player_id == 2 && obj.shoe_size == 1);
});

document.write(JSON.stringify(player))

edited Jun 01 '15 at 08:20

answered Jun 01 '15 at 08:11

Satpal

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is filter a jquery function or pure js? – Aaron Musktin Jun 01 '15 at 08:11
can it be this.player_id instead of obj.player_id? – Aaron Musktin Jun 01 '15 at 08:23
yes,thanks so much! but can I it use map or grep? What's the advantage of using filter()? – Aaron Musktin Jun 01 '15 at 08:39
@AaronMusktin `Array.prototype.map()` returns one element for every element in the original array. `Array.prototype.filter()` returns only the specific elements that return `true` in the function provided. They are used in different situations. – Phylogenesis Jun 01 '15 at 09:00

remove localstorage array object base on value

1 Answers1