PHP Notice: Undefined variable: row in

Asked May 09 '15 at 02:12

Active May 09 '15 at 02:38

Viewed 44 times

I am trying to deal with this error, it show notice undefined variable row in line.. This my code:

<?php
  include('include/db.php');
  include('include/function.php');  
  if(isset($_GET['services'])){            
        $result=$Con->query("SELECT * FROM tbl_about_n_servciesub WHERE sub_id={$_GET['services']}");
        $row=mysqli_fetch_object($result);
  echo $row->description;
  }
?>

edited May 09 '15 at 02:16

asked May 09 '15 at 02:12

DOM

3

you should read this: http://stackoverflow.com/questions/601300/what-is-sql-injection – bruchowski May 09 '15 at 02:15
What line is the undefined variable notice? – zedfoxus May 09 '15 at 02:16
You haven't declared variable $row when assigning `mysqli_fetch_object($result)` to it – Michaël Hompus May 09 '15 at 02:32
Full error message.... – Devon May 09 '15 at 02:42

PHP Notice: Undefined variable: row in

0 Answers0