inconsistent behavior of

Question

I have the following code

cout << setfill('0') << setw(4) << hex << 100 << 100 << std::endl;

The output is:

If I want to let every number with width 4, I have to use

out << setfill('0') << setw(4) << hex << 100 << sew(4) << 100 << std::endl;

But if I want to print every number with hex and setfill('0'), I only need to set setfill('0') and std::hex once.

Does c++ design this on purpose? what is its intention?

Some manipulators causes permanent state changes to the stream, some just for the next output. — Some programmer dude, Apr 29 '15 at 08:19
`setw` only applies to the next operation. All other manipulators are permanent. — Kerrek SB, Apr 29 '15 at 08:20

score 2 · Answer 1 · answered Apr 29 '15 at 08:21

2

Yes it is on purpose. The stream operations are internally peppered with resets of the field width, specified by the standard. I think there's no good answer as to why.

answered Apr 29 '15 at 08:21

Cheers and hth. - Alf

135,616
15
192
304

inconsistent behavior of

1 Answers1