I am getting an error on the 'start' in the (start + finish) at the bottom

Question

I am getting an error on the 'start' in the (start + finish) at the bottom. The only way to fix it is to add "int start = inputFn.nextInt();" below ' Scanner inputFn = new Scanner(System.in);' but that screws it all up. I was able to fix it before but I forgot how I did it. Please help.

public static void main(String eth[]){

System.out.println("Please Enter An Integer:");
Scanner inputFn = new Scanner(System.in);


if (inputFn.hasNextInt()){
}else{
int start = inputFn.nextInt();
System.out.print("Play By The Rules And Enter An Integer");

}

System.out.println("Please Enter An Integer:");
Scanner inputSn = new Scanner(System.in);
int finish = inputSn.nextInt();

int answer = (start + finish);
System.out.println(answer);


}
}

You need to declare the variable (`start` in your case) outside of the else, because it is only visible inside the declared scope. Alternatively you can put all of the second read into the else. — eckes, Apr 26 '15 at 01:16
You're declaring the `start` variable in a condition-scope and are trying to call it at method-scope. This isn't possible. Better indentation of your code would better show this as being the problem you're having. — Drew Kennedy, Apr 26 '15 at 01:17
learn to format your code in a sane manner, you can only expect the same amount of effort you put into asking the question from someone helping, right that that is not much ... — , Apr 26 '15 at 01:19

score 0 · Answer 1 · edited Apr 26 '15 at 01:14

0

The if

if (inputFn.hasNextInt()){
}else{
  int start = inputFn.nextInt();
  System.out.print("Play By The Rules And Enter An Integer");
}

is kind of backwards. You are reading the integer only if there ISN'T one. And you are defining the start variable inside the if block which is why you are getting the error.

Something more like

int start = 0;
if (inputFn.hasNextInt()){
  start = inputFn.nextInt();
}else{
  System.out.print("Play By The Rules And Enter An Integer");
}

would seem better.

edited Apr 26 '15 at 01:14

eckes

9,350
1
52
65

answered Apr 26 '15 at 01:01

Evan Williams

396
2
8

That did help. But it still doesn't get away that start error all the way at the bottom – Ethan Cotler Apr 26 '15 at 01:06
@EthanCotler, did you put the int start definition outside the if block, and if you did, what specifically is the error – Evan Williams Apr 26 '15 at 01:08
if I put "int start = inputFn.nextInt();" " below "Scanner inputFn = new Scanner(System.in);" it fixes the problem except adds an extra line in the console for user input, and I don't want that. – Ethan Cotler Apr 26 '15 at 01:08
You need to do `int start;` before the if, then inside the if `start = inputFn.nextInt();`, as in the example code I wrote. – Evan Williams Apr 26 '15 at 01:11
I added =0 to the answer, otherwise you get a "variable not initialized" error. – eckes Apr 26 '15 at 01:14
@eckes, thank you. That is what I get for typing without compiling. – Evan Williams Apr 26 '15 at 01:16

I am getting an error on the 'start' in the (start + finish) at the bottom

1 Answers1

Linked