Upload Image via URL

Question

Code:

if(isset($_POST['update_avatar'])) {
    $url = $_POST['avatar'];
    $info = getimagesize($url);

    if(isset($info['name'])) {
        echo "Exists";
    } else {
        echo "Error";
    }
}

How can I avoid getting PHP errors when the user types an invalid URL, random piece of text or invalid image URL etc?

Have a look at this answer maybe: http://stackoverflow.com/questions/7684771/how-check-if-file-exists-from-web-address-url-in-php — , Mar 03 '15 at 16:24

Barmar · Answer 1 · 2015-03-03T21:13:46.007

0

If there's an error, getimagesize returns false, so test for that. And to suppress error messages from a function, put @ before it:

$info = @getimagesize($url);
if (!$info) {
    echo "Error";
} else {
    // Process the image
}

edited Mar 03 '15 at 21:13

answered Mar 03 '15 at 16:25

Barmar

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I still get the following error either way: Warning: getimagesize(www.google.com): failed to open stream: No such file or directory in / – Jordan Mar 03 '15 at 20:01
You can use the `@` prefix to suppress error messages. – Barmar Mar 03 '15 at 21:14

score 0 · Answer 2 · answered Mar 03 '15 at 16:25

0

Use exception handling. Place your critical code into a try..catch block. You can find more information here.

answered Mar 03 '15 at 16:25

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I still get the following error either way: Warning: getimagesize(www.google.com): failed to open stream: No such file or directory in / – Jordan Mar 03 '15 at 20:01

Upload Image via URL

2 Answers2