The draft C++11 standard states that constexpr will declare an object as const:
7.1.5p9
A constexpr specifier used in an object declaration declares the object as const. Such an object shall have literal type and shall be initialized.
So it seems that constexpr const int i = 5; is redundant. However, combining const is explicitly disallowed:
7.1.6p2
const can be combined with any type specifier except itself.
Is there any reason why this rule wasn't extended to constexpr?
