The above suggestions won't work if the delimiters after the first delimiter include characters from that first delimiter. For instance, if you want to use line breaks as delimiters, but you're not sure if your input uses \r\n, \r or just \n, you can't use the above methods.
$str = '___RN___RN___R___N___RN___RN';
$del = array('RN', 'R', 'N');
# This won't work if delimiters 2, 3, n include characters from delimiter 1
var_dump(explode( $del[0], str_replace($del, $del[0], $str)));
This will output:
array(11) {
[0]=>
string(4) "___R"
[1]=>
string(0) ""
[2]=>
string(4) "___R"
[3]=>
string(0) ""
[4]=>
string(4) "___R"
[5]=>
string(3) "___"
[6]=>
string(4) "___R"
[7]=>
string(0) ""
[8]=>
string(4) "___R"
[9]=>
string(0) ""
[10]=>
string(0) ""
}
Which isn't ideal if you're planning to do string comparisons. Instead, you'll need to get a bit more complex. What I have written below may not be the most efficient and succinct, but it does the trick.
# This, however, will work
function array_explode($delimiters, $string){
if(!is_array(($delimiters)) && !is_array($string)){
//if neither the delimiter nor the string are arrays
return explode($delimiters,$string);
} else if(!is_array($delimiters) && is_array($string)) {
//if the delimiter is not an array but the string is
foreach($string as $item){
foreach(explode($delimiters, $item) as $sub_item){
$items[] = $sub_item;
}
}
return $items;
} else if(is_array($delimiters) && !is_array($string)) {
//if the delimiter is an array but the string is not
$string_array[] = $string;
foreach($delimiters as $delimiter){
$string_array = array_explode($delimiter, $string_array);
}
return $string_array;
}
}
var_dump(array_explode($del,$str));
It will output the following:
array(7) {
[0]=>
string(3) "___"
[1]=>
string(3) "___"
[2]=>
string(3) "___"
[3]=>
string(3) "___"
[4]=>
string(3) "___"
[5]=>
string(3) "___"
[6]=>
string(0) ""
}
Have a play: https://3v4l.org/bJOkI