Capturing Last match using Reg Ex

Question

My String looks likes this

Dec 04 08:14:23 198.19.71.200 Dec 04 08:14:23 198.19.71.201

Where highligted string consist of two ip address

I am using below regex to capture ip's

(\d+.\d+.\d+.\d+)

Now i want to capture the last ip. How would i capture the last ip since my regex is capturing both the ip's ?

Any help will be appreciated. Thankyou

Iterate through your captured groups and select the last one? — Kilazur, Jan 22 '15 at 15:29
I don't know, what language/tool are you working with? I mean, you're not just using regular expressions out of the blue, are you? — Kilazur, Jan 22 '15 at 15:49

score 0 · Answer 1 · answered Jan 22 '15 at 16:10

0

Use a negative look ahead:

((\d+\.){3}\d+)(?!.*(\d+\.){3}\d+)

Also slightly simplified the main regex and made it more specific to dots.

answered Jan 22 '15 at 16:10

Bohemian

1 Answers1