how to PHP if condition with browser width?

Question

I have some script like below but it does not work

<?php
$width = "<script>document.write(window.outerWidth);</script>";
$width2 = (int)$width;
echo $width2;
if ( $width2 < 800 ) { ?>
    bad
<? } else { ?>
    ok
<? } ?>

please help me ...

http://stackoverflow.com/questions/1504459/getting-the-screen-resolution-using-php — Raúl Monge, Dec 19 '14 at 08:45
php is run on the server, so the screen width can't possibily be available to it, you'd need javascript, or if your doing css based on screen size, media queries — atmd, Dec 19 '14 at 09:17

Nepal12 · Accepted Answer · 2014-12-19T09:23:42.867

0

You need JavaScript (taken from http://stackoverflow.com/questions/4180134/how-to-get-users-screen-resolution-with-php and http://stackoverflow.com/questions/1504459/getting-the-screen-resolution-using-php)

var screenWidth = window.screen.width,
    screenHeight = window.screen.height;
You can then send it to the server via Ajax (with an XmlHttpRequest).

See also the MDC window.screen docs.

edited Dec 19 '14 at 09:23

answered Dec 19 '14 at 08:44

Nepal12

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score 0 · Answer 2 · answered Dec 19 '14 at 09:21

You mixed JavaScript and PHP.

<script>document.write(window.outerWidth);</script>

You cannot execute that JavaScript in PHP.

If you what to get browser width, you have to write a JavaScript and put it into browser to execute. The JavaScript should sent the size to server by AJAX/form post.

how to PHP if condition with browser width?

2 Answers2