conversion datatype assign in java

Question

I don't understand why i should use {b=(byte) i} or {i =(int) d} this to conversion . Please can say me cordially why it happens in conversion. My sample code below.

public class Conversion {

    public static void main(String[] args) {
        byte b;
        int i = 257;
        double d = 323.142;
        System.out.println("\n Conversion int to byt");
        b = (byte) i;
        System.out.println("i and b "+i+ " after "+b);

        System.out.println("\n Conversion int to byt");
        i = (int) d;
        System.out.println("d and i "+d+ " after "+i);

    }

}

And I don't understand your question. – TheLostMind Nov 10 '14 at 09:48 — TheLostMind, Nov 10 '14 at 09:48

score 0 · Answer 1 · answered Nov 10 '14 at 09:51

0

You are doing "Widening Primitive Conversion" and "Narrowing Primitive Conversion".

https://docs.oracle.com/javase/specs/jls/se7/html/jls-5.html#jls-5.1.2 https://docs.oracle.com/javase/specs/jls/se7/html/jls-5.html#jls-5.1.3

answered Nov 10 '14 at 09:51

Lakatos Gyula

3,529
4
28
52

score 0 · Accepted Answer · edited May 23 '17 at 12:27

byte have range from -128 to 127 if you exceeds its limit you have to explicitly cast it to int the same way int have range and if it exceeds from its range you have to explicitly cast it

if we have value of byte in between the range of -128 to 127 there is no requirement of explicitly cast it to int

for more help i have follow link which will guide you

conversion datatype assign in java

2 Answers2