Here is my storyboard configuration:
Navigation Controller -> View Controller A -> Push-> View Controller B
^
|
Modal
^
|
View Controller C
What I want to achieve: When a button is pressed in View C, directly View B will be opened modally (No part of View A is to be displayed). Also, View B will have a navigation back button to View A.
To achieve this,
- I set up the illustrated storyboard.
- I created a segue between View C and the Navigation Controller of View A/B.
- In the 'prepareForSegue' method of View Controller C, I get an instance of View Controller A as the first element in the navigation. In this instance, I set a variable like 'directlyProceedToViewB=YES'.
- In the viewDidLoad method of View Controller A, I check the variable 'directlyProceedToViewB' and if it is YES, I call 'performSegueWithIdentifier' to segue to View B
The result is so that, first View A is opened modally and after displaying it a very short time, View B is opened with a push animation (View B can navigate back to View A, which is good). But I do not want View A to be displayed any time at all. How can I achieve this?
EDIT:
To better visualize, I'm adding a screenshot with more example cases to support:
Here are some cases I want to support:
- We can start with ViewC, click on 'Modally Display B' which opens ViewB, then click 'Back to A' to navigate back to ViewA, then click on 'Dismiss Modal' on ViewA to go back to ViewC
- We can start with ViewD, clcik on 'Modally Display A' which opens ViewA, then click on 'PushB' to open ViewB, then go back and forth between A and B and modally dismiss to ViewD.