So the Clojure go-block stops translation at function boundaries, for many reasons, but the biggest is simplicity. This is most commonly seen when constructing a lazy seq:
(go (lazy-seq (<! c)))
Gets compiled into something like this:
(go (clojure.lang.LazySeq. (fn [] (<! c))))
Now let's think about this real quick...what should this return? Assuming what you probably wanted was a lazy seq containing the value taken from c, but the <! needs to translate the remaining code of the function into a callback, but LazySeq is expecting the function to be synchronous. There really isn't a way around this limitation.
So back to your question if, you macroexpand for you'll see that it doesn't actually loop, instead it expands into a bunch of code that eventually calls lazy-seq and so parking ops don't work inside the body. doseq (and dotimes) however are backed by loop/recur and so those will work perfectly fine.
There are a few other places where this might trip you up with-bindings being one example. Basically if a macro sticks your core.async parking operations into a nested function, you'll get this error.
My suggestion then is to keep the body of your go blocks as simple as possible. Write pure functions, and then treat the body of go blocks as the places to do IO.
------------ EDIT -------------
By stops translation at function boundaries, I mean this: the go block takes its body and translates it into a state-machine. Each call to <! >! or alts! (and a few others) are considered state machine transitions where the execution of the block can pause. At each of those points the machine is turned into a callback and attached to the channel. When this macro reaches a fn form it stops translating. So you can only make calls to <! from inside a go block, not inside a function inside a code block.
This is part of the magic of core.async. Without the go macro, core.async code would look a lot like callback-hell in other langauges.
