function hoisting in javascript

Asked Sep 22 '14 at 15:05

Active Sep 22 '14 at 15:16

Viewed 100 times

I was just trying function hoisting in js , I have a doubt in below code

// Case 1
var foo = function() {
    return 3;
}

// Case 2
function foo() {
    return 2;    
}
alert(foo());

Why case1 gets preference over case 2 always? case 2 never overrides case 1 , why?

edited Sep 22 '14 at 15:08

jayelm

asked Sep 22 '14 at 15:05

Bhupendra

1

http://stackoverflow.com/questions/336859/var-functionname-function-vs-function-functionname – epascarello Sep 22 '14 at 15:09
In function expression(case 1): only the variable foo is hoisted. Not the function body. In function statement(case 2): the entire function foo is hoisted to the top – Shibbir Ahmed Sep 22 '14 at 15:11
1

I don't think the "Usual" functions link answers this question. The question is specifically about "hoisting," which @Shibbir explains in his comment. – Rick Hitchcock Sep 22 '14 at 15:14
@epascarello's link is a better reason for closing the question. – Rick Hitchcock Sep 22 '14 at 15:16
@RickHitchcock: Done :-) – Bergi Sep 22 '14 at 15:16

0 Answers0