I have an Invitation
model that represents an invitation to join a subscription. There should only be one Invitation
at any given time with a specific email
/ subscription_id
combination unless the other records with the matching email
/ subscription_id
also have a state
of 'declined'
.
I can currently validate for uniqueness given that the email and subscription_id combination is unique:
My Invitation
model:
validates :email, :uniqueness => { :scope => :subscription_id }
Rspec (passes):
it { should validate_uniqueness_of(:email).scoped_to(:subscription_id) }
However, I want to skip the uniqueness check if the matching model(s) in the database have a state
that is equal to 'declined'
.
If the existing model's state is 'declined', the validation should pass.
The first thing that comes to mind is:
validates :email, :uniqueness => { :scope => :subscription_id },
:unless => lambda { |asset| asset.state == 'declined' }
But this is wrong because it checks if the newly created model has a state of 'declined', I want to check if the previously existing records have a state of 'declined'
.
I also tried this:
validates :email, :uniqueness => { :scope => :subscription_id, :message => 'subscriptionery do' },
:if => lambda { |asset| asset.state == 'declined' }
But that fails for what I assume is the same reason.
How would I write a validation that checks an additional scope?
I feel like writing something like the following, but this is just made up syntax to help explain my idea:
it { should validate_uniqueness_of(:email).scoped_to(:subscription_id) }
unless MyModel.where(:email == new_object.email,
:subscription_id == new_object.subscription_id,
:state == 'declined')
Update:
I did this and it worked:
validates :email, uniqueness: { scope: :subscription_id, message: 'The email address %{value} is already associated with this subscription.' }, if: :state_of_others_are_not_declined?, on: :create
def state_of_others_are_not_declined?
Invitation.where(email: email).where(subscription_id: subscription_id).where.not(state: 'declined').any?
end