Format JavaScript date as yyyy-mm-dd

Question

I have a date with the format Sun May 11,2014. How can I convert it to 2014-05-11 using JavaScript?

function taskDate(dateMilli) {
    var d = (new Date(dateMilli) + '').split(' ');
    d[2] = d[2] + ',';

    return [d[0], d[1], d[2], d[3]].join(' ');
}

var datemilli = Date.parse('Sun May 11,2014');
console.log(taskDate(datemilli));

The code above gives me the same date format, sun may 11,2014. How can I fix this?

I doubt that the above code gives you anything else than a syntax error. — plalx, May 11 '14 at 13:16
Really consider using a library like Moment.js. It will format in desired result :) — Ankur, Jan 28 '16 at 19:14
Why using a library when 5 line of code can do the work ? @Ankur — Black Mamba, May 15 '17 at 07:15
Possible duplicate of [Where can I find documentation on formatting a date in JavaScript?](https://stackoverflow.com/questions/1056728/where-can-i-find-documentation-on-formatting-a-date-in-javascript) — Heretic Monkey, Jul 11 '18 at 18:08
Related: [What are valid Date Time Strings in JavaScript?](https://stackoverflow.com/questions/51715259/what-are-valid-date-time-strings-in-javascript/) Note that "Sun May 11,2014" is not a valid date string and parsing it might fail in some browsers. — str, Feb 09 '19 at 12:33

score 747 · Accepted Answer · edited Feb 13 '21 at 22:03

747

You can do:

function formatDate(date) {
    var d = new Date(date),
        month = '' + (d.getMonth() + 1),
        day = '' + d.getDate(),
        year = d.getFullYear();

    if (month.length < 2) 
        month = '0' + month;
    if (day.length < 2) 
        day = '0' + day;

    return [year, month, day].join('-');
}
 
console.log(formatDate('Sun May 11,2014'));

Usage example:

console.log(formatDate('Sun May 11,2014'));

Output:

2014-05-11

Demo on JSFiddle: http://jsfiddle.net/abdulrauf6182012/2Frm3/

edited Feb 13 '21 at 22:03

Kos

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answered May 11 '14 at 13:18

user3470953

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Really multiple variable declarations in the same statement? http://stackoverflow.com/questions/694102/declaring-multiple-variables-in-javascript – bhspencer Aug 29 '15 at 15:00
17

@Fuser97381 Multiple variable declarations in the same statement is more than just an aesthetic style preference. It is a dangerous practice. If you inadvertently fail add a comma after each declaration you end up creating global variables. Not something that should be encouraged on what may become the canonical answer to a question. – bhspencer Aug 31 '15 at 12:13
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`'use strict';` @bhspencer – Vix Oct 20 '15 at 14:11
4

Reformatting a date string should not depend on successful parsing of non-standard strings by the built-in parser. Given the OP format, it can be reformatted in less code without using a Date at all. – RobG Jun 16 '17 at 12:12
How to increment more 30 days in range 1~31? – Steve Angello Feb 22 '19 at 16:19
What about doing the other way around: turn `2014-05-11` into `May 5, 2014`? – Razvan Zamfir Feb 25 '19 at 22:05
@RazvanZamfir check toLocaleDateString, it may be a cleaner way to output the format you seek: https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/Date/toLocaleDateString – Douglas Schmidt Sep 25 '19 at 20:25
8

this works like a charm but I don't understand why javascript does not have a native solution for this... I mean, we are in 2020 and date is an important aspect to web apps. – babaliaris Mar 04 '20 at 07:24
What I find interesting ist that, that this solution has two times better performance, than the one with `toISOString` – matvs May 14 '21 at 18:41

score 747 · Answer 2 · edited Apr 14 '21 at 17:02

747

Just leverage the built-in toISOString method that brings your date to the ISO 8601 format:

const yourDate = new Date()
yourDate.toISOString().split('T')[0]

Where yourDate is your date object.

Edit: @exbuddha wrote this to handle time zone in the comments:

const offset = yourDate.getTimezoneOffset()
yourDate = new Date(yourDate.getTime() - (offset*60*1000))
return yourDate.toISOString().split('T')[0]

edited Apr 14 '21 at 17:02

laconbass

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answered Apr 21 '15 at 13:51

Darth Egregious

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BE CAREFUL with this method as it first converts to the date to UTC. If you are in a + timezone and your time portion is early in the day, then it could roll-back a day. Alternatively, if you're in a - timezone and your time portion is late in the day, then it could roll forward a day. – Luke Baulch Sep 13 '15 at 02:47
12

Try this instead: `new Date(yourDateStr).toISOString().split('T')[0]` – exbuddha Feb 12 '16 at 19:42
33

`const offset = yourDate.getTimezoneOffset(); yourDate = new Date(yourDate.getTime() + (offset*60*1000)); yourDate.toISOString().split('T')[0]` this should solve the issue of timezone – mjwrazor Feb 14 '18 at 17:11
2

How come this has 123 votes? My timezone is `+05:00` and `var yourDate = new Date(2018, 3 - 1, 26); yourDate.toISOString().split('T')[0];` gives me `"2018-03-25"`. – Salman A Mar 26 '18 at 18:19
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`now.toISOString().substring(0,10);` This is a cleaner alternative, since it reminds you that `YYYY-MM-DD` are the first ten characters of the complete iso format – Gutimore Aug 26 '18 at 23:47
@SalmanA As Luke mentions, the date is converted in UTC when shown in ISO string (an ISO string is in UTC). The +5 being converted makes the day fall before midnight, as by default Date will be constructed at hour 00h00. – Félix Gagnon-Grenier May 29 '19 at 12:38
@SalmanA I... see. That was not my impression of that comment, following the wonder upon the votes. I hope you did not feel condescended upon. – Félix Gagnon-Grenier May 29 '19 at 20:57
If you use toISOString, it is easier if you encode your date using UTC in the first place: utcDate1 = new Date(Date.UTC(2020, 0, 1)) -> Wed Jan 01 2020 01:00:00 GMT+0100 (Central European Standard Time) utcDate1.toISOString()-> "2020-01-01T00:00:00.000Z" .Any date/datetime you encode using .UTC will map exactly back as you expect when using .toISOString() . – KenBuckley Mar 03 '20 at 08:32
7

Note: using the helpful solution commented by @mjwrazor, I had to subtract instead of add the offset to get the correct date (change the `+ (offset` to a `- (offset`) – rococo Mar 20 '20 at 02:10
2

@rococo you either add or subtract depending on your orientation from UTC 0. Which is England. – mjwrazor Mar 24 '20 at 14:37
@KenBuckley The question is how to get the date in YYYY-MM-DD format. Your comment _assumes_ that value is already available, so it doesn't apply here. – Tim Hobbs Jan 15 '21 at 01:19
Dirty, but it works ;) - @TimHobbs The `new Date()` construct allows generating the `Date` object – laconbass Apr 14 '21 at 17:04

score 219 · Answer 3 · edited Mar 25 '21 at 16:27

219

I use this way to get the date in format yyyy-mm-dd :)

var todayDate = new Date().toISOString().slice(0, 10);
console.log(todayDate);

edited Mar 25 '21 at 16:27

Ruslan López

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answered Jul 01 '16 at 15:11

Fernando Aguilar

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How do you handle the date switching by a day as mentioned here by @Luke_Baulch? – Malvineous Sep 10 '16 at 13:45
10

You can do this: var todayDate = new Date(); todayDate.setMinutes(todayDate.getMinutes() - todayDate.getTimezoneOffset()); todayDate.toISOString().slice(0,10); This should help avoid the UTC problem. – Fernando Aguilar Sep 12 '16 at 15:44
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@FernandoAguilar One doubt though, how do we know we need to subtract the offset or add it? – whyAto8 Apr 12 '17 at 10:40
`var todayDate = new Date(2018, 3 - 1, 26); todayDate.toISOString().slice(0, 10);` gives me `"2018-03-25"`. On another system `var todayDate = new Date(2018, 3 - 1, 26, 17, 0, 0); todayDate.toISOString().slice(0, 10);` gives me `"2018-03-27"`. – Salman A Mar 26 '18 at 18:22
7

Doesn't always work. It sometimes subtracts a day due to UTC conversion. – NickG May 22 '19 at 11:55
slicing strings is to bad practice – Даниил Пронин Oct 19 '20 at 07:38
UTC!!!! in australia we are +10 timezone. Because I tend to fix things in afternoon it has taken me a week to find this. – KenF Feb 25 '21 at 00:13

score 158 · Answer 4 · edited Sep 07 '19 at 12:59

158

The simplest way to convert your date to the yyyy-mm-dd format, is to do this:

var date = new Date("Sun May 11,2014");
var dateString = new Date(date.getTime() - (date.getTimezoneOffset() * 60000 ))
                    .toISOString()
                    .split("T")[0];

How it works:

new Date("Sun May 11,2014") converts the string "Sun May 11,2014" to a date object that represents the time Sun May 11 2014 00:00:00 in a timezone based on current locale (host system settings)
new Date(date.getTime() - (date.getTimezoneOffset() * 60000 )) converts your date to a date object that corresponds with the time Sun May 11 2014 00:00:00 in UTC (standard time) by subtracting the time zone offset
.toISOString() converts the date object to an ISO 8601 string 2014-05-11T00:00:00.000Z
.split("T") splits the string to array ["2014-05-11", "00:00:00.000Z"]
[0] takes the first element of that array

Demo

var date = new Date("Sun May 11,2014");
var dateString = new Date(date.getTime() - (date.getTimezoneOffset() * 60000 ))
                    .toISOString()
                    .split("T")[0];

console.log(dateString);

edited Sep 07 '19 at 12:59

Peter Mortensen

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answered May 02 '18 at 08:34

John Slegers

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No one else is aghast that this is the simplest way?? – gap Aug 27 '19 at 17:29
.toISOString() doesn't work correctly with daylight savings though. – Joe's Ideas Nov 25 '19 at 06:00
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@JoeDevmon : I don't see how that's relevant here. The `- (date.getTimezoneOffset() * 60000 )` bit should eliminate any timezone differences, including the impact of daylight savings time. – John Slegers Nov 25 '19 at 09:42
2

@JohnSlegers that's what I was thinking, but then I was still getting the day before in some cases. I refactored and your example works now. I must have had a weird date string or something. Thanks for sticking with it and pointing that out. +1 – Joe's Ideas Nov 26 '19 at 01:09
3

I've searched high and low across SO and other sites to find the best way to deal with timezone issues with dates in JS, and hands down, this is by far the easiest and the best. Thank you! – HartleySan Mar 31 '20 at 13:44
It sad but it is simpliest way to format js date to string you need. I'm new in js, but in java it is 100 times easier to format date to any format. That is why was thinking there are easier way, but after I tried different solutions I choose this one. Thank you for your answer. – Юрий Яхница May 15 '20 at 10:52

Juanma Menendez · Answer 5 · 2020-10-06T16:46:47.053

2020 ANSWER

You can use the native .toLocaleDateString() function which supports several useful params like locale (to select a format like MM/DD/YYYY or YYYY/MM/DD), timezone (to convert the date) and formats details options (eg: 1 vs 01 vs January).

Examples

new Date().toLocaleDateString() // 8/19/2020

new Date().toLocaleDateString('en-US', {year: 'numeric', month: '2-digit', day: '2-digit'}); // 08/19/2020 (month and day with two digits)

new Date().toLocaleDateString('en-ZA'); // 2020/08/19 (year/month/day) notice the different locale

new Date().toLocaleDateString('en-CA'); // 2020-08-19 (year-month-day) notice the different locale

new Date().toLocaleString("en-US", {timeZone: "America/New_York"}); // 8/19/2020, 9:29:51 AM. (date and time in a specific timezone)

new Date().toLocaleString("en-US", {hour: '2-digit', hour12: false, timeZone: "America/New_York"});  // 09 (just the hour)

Notice that sometimes to output a date in your specific desire format, you have to find a compatible locale with that format. You can find the locale examples here: https://www.w3schools.com/jsref/tryit.asp?filename=tryjsref_tolocalestring_date_all

Please notice that locale just change the format, if you want to transform a specific date to a specific country or city time equivalent then you need to use the timezone param.

This still suffers from problems with timezones as it is based off UTC, so you still have to jump all the hoops of determining the offset and altering the date. — Tim Hobbs, Jan 15 '21 at 01:22
@TimHobbs you can set the timezone you want eg: ("timeZone: "America/New_York") and the date will be converted to that timezone. — Juanma Menendez, Jan 15 '21 at 03:34
For my case where I didn't need the time zones, `new Date().toLocaleDateString('en-CA')` was perfect — Qarun Qadir Bissoondial, Jan 19 '21 at 03:01

score 48 · Answer 6 · edited Jan 04 '21 at 22:51

48

format = function date2str(x, y) {
    var z = {
        M: x.getMonth() + 1,
        d: x.getDate(),
        h: x.getHours(),
        m: x.getMinutes(),
        s: x.getSeconds()
    };
    y = y.replace(/(M+|d+|h+|m+|s+)/g, function(v) {
        return ((v.length > 1 ? "0" : "") + z[v.slice(-1)]).slice(-2)
    });

    return y.replace(/(y+)/g, function(v) {
        return x.getFullYear().toString().slice(-v.length)
    });
}

Result:

format(new Date('Sun May 11,2014'), 'yyyy-MM-dd')
"2014-05-11

edited Jan 04 '21 at 22:51

AJP

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orangleliu

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I like the additional flexibility that this solution gives over the other answers to this question. I haven't thoroughly tested this, but for the format I desired (i.e. "yyyy-MM-dd hh:mm:ss"), it works just as expected. – porcus Mar 20 '15 at 02:37
8

You could eaaaaaaaasily avoid `eval`. – Salman A Mar 27 '18 at 07:59
4

here's a version which avoids the eval and comments better https://jsfiddle.net/8904cmLd/2/ – m1m1k Apr 05 '18 at 11:53
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I benefited from this response. I did replace that line with the eval statement to `return ((v.length > 1 ? "0" : "") + z[v.slice(-1)]).slice(-2);` – JesusIsMyDriver.dll Oct 10 '18 at 20:36
"H" should be capitalized, not "h" (small) – DavidDunham Mar 03 '21 at 08:06

score 47 · Answer 7 · answered Dec 15 '15 at 13:10

47

A combination of some of the answers:

var d = new Date(date);
date = [
  d.getFullYear(),
  ('0' + (d.getMonth() + 1)).slice(-2),
  ('0' + d.getDate()).slice(-2)
].join('-');

answered Dec 15 '15 at 13:10

aqwsez

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I like the solution the best - easy to read, and does not rely on `toISOString()` and the potential timezone pitfalls with using that function. – mfcallahan May 12 '19 at 16:59
9

this is the first one that doesn't make my brain hurt. – ckapilla Apr 12 '20 at 23:17

score 36 · Answer 8 · edited Sep 07 '19 at 13:01

36

If you don't have anything against using libraries, you could just use the Moments.js library like so:

var now = new Date();
var dateString = moment(now).format('YYYY-MM-DD');

var dateStringWithTime = moment(now).format('YYYY-MM-DD HH:mm:ss');

<script src="https://cdnjs.cloudflare.com/ajax/libs/moment.js/2.18.1/moment.min.js"></script>

edited Sep 07 '19 at 13:01

Peter Mortensen

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answered Sep 11 '18 at 16:14

Nifemi Sola-Ojo

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Cool solution, but its a 300kb package – Adam May 28 '20 at 13:55
Applied in react project: `npm install moment --save` `import moment from 'moment';` `const showEventDate = moment(your-date-here).format('YYYY-MM-DD; HH:mm A');` A pure solution for presenting date/time in any format. It gives local date-time with AM/PM and whatever you need just changing the format. [Moment.js](https://momentjs.com/) also provides easy date/time counting solution. – TradeCoder Dec 07 '20 at 06:59
@theTradeCoder as Adam mentioned above the size of moment is pretty large (I think it is more like 67kb, but still) so you should consider that when evaluating the ease of use and utility of any dependency. There are smaller alternatives (day.js = 2kb). – Tim Hobbs Jan 15 '21 at 01:27
1

Just an update about the `moment.js` library that - `moment.js` is already discontinued. – Rafik Farhad Mar 10 '21 at 13:10

Aleksandr Belugin · Answer 9 · 2020-02-01T00:33:53.793

You can use toLocaleDateString('fr-CA') on Date object

console.log(new Date('Sun May 11,2014').toLocaleDateString('fr-CA'));

Also I found out that those locales give right result from this locales list List of All Locales and Their Short Codes?

'en-CA'
'fr-CA'
'lt-LT'
'sv-FI'
'sv-SE'

var localesList = ["af-ZA",
  "am-ET",
  "ar-AE",
  "ar-BH",
  "ar-DZ",
  "ar-EG",
  "ar-IQ",
  "ar-JO",
  "ar-KW",
  "ar-LB",
  "ar-LY",
  "ar-MA",
  "arn-CL",
  "ar-OM",
  "ar-QA",
  "ar-SA",
  "ar-SY",
  "ar-TN",
  "ar-YE",
  "as-IN",
  "az-Cyrl-AZ",
  "az-Latn-AZ",
  "ba-RU",
  "be-BY",
  "bg-BG",
  "bn-BD",
  "bn-IN",
  "bo-CN",
  "br-FR",
  "bs-Cyrl-BA",
  "bs-Latn-BA",
  "ca-ES",
  "co-FR",
  "cs-CZ",
  "cy-GB",
  "da-DK",
  "de-AT",
  "de-CH",
  "de-DE",
  "de-LI",
  "de-LU",
  "dsb-DE",
  "dv-MV",
  "el-GR",
  "en-029",
  "en-AU",
  "en-BZ",
  "en-CA",
  "en-GB",
  "en-IE",
  "en-IN",
  "en-JM",
  "en-MY",
  "en-NZ",
  "en-PH",
  "en-SG",
  "en-TT",
  "en-US",
  "en-ZA",
  "en-ZW",
  "es-AR",
  "es-BO",
  "es-CL",
  "es-CO",
  "es-CR",
  "es-DO",
  "es-EC",
  "es-ES",
  "es-GT",
  "es-HN",
  "es-MX",
  "es-NI",
  "es-PA",
  "es-PE",
  "es-PR",
  "es-PY",
  "es-SV",
  "es-US",
  "es-UY",
  "es-VE",
  "et-EE",
  "eu-ES",
  "fa-IR",
  "fi-FI",
  "fil-PH",
  "fo-FO",
  "fr-BE",
  "fr-CA",
  "fr-CH",
  "fr-FR",
  "fr-LU",
  "fr-MC",
  "fy-NL",
  "ga-IE",
  "gd-GB",
  "gl-ES",
  "gsw-FR",
  "gu-IN",
  "ha-Latn-NG",
  "he-IL",
  "hi-IN",
  "hr-BA",
  "hr-HR",
  "hsb-DE",
  "hu-HU",
  "hy-AM",
  "id-ID",
  "ig-NG",
  "ii-CN",
  "is-IS",
  "it-CH",
  "it-IT",
  "iu-Cans-CA",
  "iu-Latn-CA",
  "ja-JP",
  "ka-GE",
  "kk-KZ",
  "kl-GL",
  "km-KH",
  "kn-IN",
  "kok-IN",
  "ko-KR",
  "ky-KG",
  "lb-LU",
  "lo-LA",
  "lt-LT",
  "lv-LV",
  "mi-NZ",
  "mk-MK",
  "ml-IN",
  "mn-MN",
  "mn-Mong-CN",
  "moh-CA",
  "mr-IN",
  "ms-BN",
  "ms-MY",
  "mt-MT",
  "nb-NO",
  "ne-NP",
  "nl-BE",
  "nl-NL",
  "nn-NO",
  "nso-ZA",
  "oc-FR",
  "or-IN",
  "pa-IN",
  "pl-PL",
  "prs-AF",
  "ps-AF",
  "pt-BR",
  "pt-PT",
  "qut-GT",
  "quz-BO",
  "quz-EC",
  "quz-PE",
  "rm-CH",
  "ro-RO",
  "ru-RU",
  "rw-RW",
  "sah-RU",
  "sa-IN",
  "se-FI",
  "se-NO",
  "se-SE",
  "si-LK",
  "sk-SK",
  "sl-SI",
  "sma-NO",
  "sma-SE",
  "smj-NO",
  "smj-SE",
  "smn-FI",
  "sms-FI",
  "sq-AL",
  "sr-Cyrl-BA",
  "sr-Cyrl-CS",
  "sr-Cyrl-ME",
  "sr-Cyrl-RS",
  "sr-Latn-BA",
  "sr-Latn-CS",
  "sr-Latn-ME",
  "sr-Latn-RS",
  "sv-FI",
  "sv-SE",
  "sw-KE",
  "syr-SY",
  "ta-IN",
  "te-IN",
  "tg-Cyrl-TJ",
  "th-TH",
  "tk-TM",
  "tn-ZA",
  "tr-TR",
  "tt-RU",
  "tzm-Latn-DZ",
  "ug-CN",
  "uk-UA",
  "ur-PK",
  "uz-Cyrl-UZ",
  "uz-Latn-UZ",
  "vi-VN",
  "wo-SN",
  "xh-ZA",
  "yo-NG",
  "zh-CN",
  "zh-HK",
  "zh-MO",
  "zh-SG",
  "zh-TW",
  "zu-ZA"
];

localesList.forEach(lcl => {
  if ("2014-05-11" === new Date('Sun May 11,2014').toLocaleDateString(lcl)) {
    console.log(lcl, new Date('Sun May 11,2014').toLocaleDateString(lcl));
  }
});

Any idea _why_ this works? Is ISO format just the default, or do these locales genuinely use that format? If it's the former I'd be concerned that it could change unexpectedly in the future. — jymbob, Feb 25 '20 at 11:13
@jymbob I think these locales genuinely use those formats. I've came to the same answer by looking at this Wikipedia page: https://en.wikipedia.org/wiki/Date_format_by_country — Ciprian Tomoiagă, Apr 17 '20 at 13:31

score 18 · Answer 10 · edited Sep 07 '19 at 13:44

18

Simply use this:

var date = new Date('1970-01-01'); // Or your date here
console.log((date.getMonth() + 1) + '/' + date.getDate() + '/' +  date.getFullYear());

Simple and sweet ;)

edited Sep 07 '19 at 13:44

Peter Mortensen

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answered Jan 13 '17 at 10:04

Pardeep Jain

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padding is not there for 2 letter format. it'll show single digit if date or month is less than 10 that's why can't use this directly. – Yatender Singh Mar 21 '17 at 03:15
yess but that can be achived simply using javascript, its totaly upto your requirement i think so , isn't it ? @YatenderSingh – Pardeep Jain Mar 21 '17 at 05:13
5

yeah correct but check the title of question "yyyy-mm-dd" format he wants :) – Yatender Singh Mar 21 '17 at 11:20
var old_date = new Date(date); var new_date = old_date.getFullYear() + '-' + (old_date.getMonth() + 1) + '-' + old_date.getDate() – Sitti Munirah Abdul Razak Dec 23 '19 at 07:14

Luo Jiong Hui · Answer 11 · 2020-01-20T15:15:50.217

13

Retrieve year, month, and day, and then put them together. Straight, simple, and accurate.

function formatDate(date) {
    var year = date.getFullYear().toString();
    var month = (date.getMonth() + 101).toString().substring(1);
    var day = (date.getDate() + 100).toString().substring(1);
    return year + "-" + month + "-" + day;
}

//Usage example:
alert(formatDate(new Date()));

edited Jan 20 '20 at 15:15

answered Nov 08 '17 at 16:21

Luo Jiong Hui

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score 12 · Answer 12 · edited Sep 07 '19 at 13:48

toISOString() assumes your date is local time and converts it to UTC. You will get an incorrect date string.

The following method should return what you need.

Date.prototype.yyyymmdd = function() {         

    var yyyy = this.getFullYear().toString();                                    
    var mm = (this.getMonth()+1).toString(); // getMonth() is zero-based         
    var dd  = this.getDate().toString();             

    return yyyy + '-' + (mm[1]?mm:"0"+mm[0]) + '-' + (dd[1]?dd:"0"+dd[0]);
};

Source: https://blog.justin.kelly.org.au/simple-javascript-function-to-format-the-date-as-yyyy-mm-dd/

Kamil Kiełczewski · Answer 13 · 2020-08-26T08:30:11.670

12

Shortest

.toJSON().slice(0,10);

var d = new Date('Sun May 11,2014' +' UTC');   // Parse as UTC
let str = d.toJSON().slice(0,10);              // Show as UTC

console.log(str);

edited Aug 26 '20 at 08:30

answered Aug 25 '20 at 21:49

Kamil Kiełczewski

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1

This doesn't work when the client is ahead of the UTC and the date in the UTC time is one day behind the current client date. – Kunal Sep 08 '20 at 16:24
1

@Kunal can you provide screenshot after run above snippet (with code and result) - using e.g. https://imgur.com/ which shows the problem? – Kamil Kiełczewski Sep 08 '20 at 16:51

score 6 · Answer 14 · edited Sep 07 '19 at 13:41

6

You can try this: https://www.npmjs.com/package/timesolver

npm i timesolver

Use it in your code:

const timeSolver = require('timeSolver');
const date = new Date();
const dateString = timeSolver.getString(date, "YYYY-MM-DD");

You can get the date string by using this method:

getString

edited Sep 07 '19 at 13:41

Peter Mortensen

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answered Jul 02 '16 at 06:45

sean1093

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score 6 · Answer 15 · edited Sep 07 '19 at 13:01

6

To consider the timezone also, this one-liner should be good without any library:

new Date().toLocaleString("en-IN", {timeZone: "Asia/Kolkata"}).split(',')[0]

edited Sep 07 '19 at 13:01

Peter Mortensen

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answered Oct 04 '18 at 17:27

krsoni

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score 5 · Answer 16 · edited Sep 07 '19 at 12:47

5

I suggest using something like formatDate-js instead of trying to replicate it every time. Just use a library that supports all the major strftime actions.

new Date().format("%Y-%m-%d")

edited Sep 07 '19 at 12:47

Peter Mortensen

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answered Dec 09 '14 at 11:01

Michael Baldry

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score 5 · Answer 17 · answered Jul 14 '20 at 08:49

5

When ES2018 rolls around (works in chrome) you can simply regex it

(new Date())
    .toISOString()
    .replace(
        /^(?<year>\d+)-(?<month>\d+)-(?<day>\d+)T.*$/,
        '$<year>-$<month>-$<day>'
    )

2020-07-14

Or if you'd like something pretty versatile with no libraries whatsoever

(new Date())
    .toISOString()
    .match(
        /^(?<yyyy>\d\d(?<yy>\d\d))-(?<mm>0?(?<m>\d+))-(?<dd>0?(?<d>\d+))T(?<HH>0?(?<H>\d+)):(?<MM>0?(?<M>\d+)):(?<SSS>(?<SS>0?(?<S>\d+))\.\d+)(?<timezone>[A-Z][\dA-Z.-:]*)$/
    )
    .groups

Which results in extracting the following

{
    H: "8"
    HH: "08"
    M: "45"
    MM: "45"
    S: "42"
    SS: "42"
    SSS: "42.855"
    d: "14"
    dd: "14"
    m: "7"
    mm: "07"
    timezone: "Z"
    yy: "20"
    yyyy: "2020"
}

Which you can use like so with replace(..., '$<d>/$<m>/\'$<yy> @ $<H>:$<MM>') as at the top instead of .match(...).groups to get

14/7/'20 @ 8:45

answered Jul 14 '20 at 08:49

Hashbrown

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There are several simpler ways to butcher the `toISOString` string which were already posted before this one. For people who are willing to tolerate the potential inaccuracy of using `toISOString`, the sheer overhead and code bloat makes this a solution that no one should consider (the first snippet anyway). – mickmackusa Sep 18 '20 at 07:00
2

Look, man, unless you're trying to reparse dates literally [hundreds of thousands of times in a matter of seconds](https://measurethat.net/Benchmarks/Show/9652/0/i-suppose-you-think-we-should-write-in-assembly) you're not going to see *any difference at all*, so I don't know where you get off calling it bloat. Like with any other *novel* answer added to an old, already-answered question; this provides the reader with choice, and maybe, knowledge ("gee, I didnt know regex could do that!"). The reader should know whether or not an answer is appropriate for their usecase, and you insult them. – Hashbrown Sep 19 '20 at 05:13
I never mentioned performance so you can leave the argument about 100,000 iterations. My point is that earlier answers provided simpler techniques. – mickmackusa Sep 19 '20 at 05:17
1

Yes, but not readable, or easily extensible. You called it bloat, which is literally `code...that is perceived as unnecessarily long, slow, or otherwise wasteful of resources`. SO is primarily *for knowledge*, so yes, even though the literal question has been answered, sometimes there are other angles that others (and at least already literally `3▲`) find might useful! Imagine that. `I don't play the "Fastest Gun In The West" game, so when you see me post a late answer, it is because I have something valuable to offer and I hope that you will acknowledge the care that I take.` -some hypocrite – Hashbrown Sep 19 '20 at 05:22
1

Nothing hypocritical going on here. I am very clear about how the first snippet is far less attractive than simply calling `.slice(0,10)`. `slice()` is much more concise, direct, readable. I love regex but not for this question. See how I am not attacking you as a person? I am judging your answer to this question. – mickmackusa Sep 19 '20 at 07:20

Ado Ren · Answer 18 · 2020-10-06T07:17:54.853

const formatDate = d => [
    d.getFullYear(),
    (d.getMonth() + 1).toString().padStart(2, '0'),
    d.getDate().toString().padStart(2, '0')
].join('-');

You can make use of padstart.

padStart(n, '0') ensures that a minimum of n characters are in a string and prepends it with '0's until that length is reached.

join('-') concatenates an array, adding '-' symbol between every elements.

getMonth() starts at 0 hence the +1.

score 4 · Answer 19 · edited Sep 07 '19 at 12:52

None of these answers quite satisfied me. I wanted a cross-platform solution that gave me the day in the local timezone without using any external libraries.

This is what I came up with:

function localDay(time) {
  var minutesOffset = time.getTimezoneOffset()
  var millisecondsOffset = minutesOffset*60*1000
  var local = new Date(time - millisecondsOffset)
  return local.toISOString().substr(0, 10)
}

That should return the day of the date, in YYYY-MM-DD format, in the timezone the date references.

So for example, localDay(new Date("2017-08-24T03:29:22.099Z")) will return "2017-08-23" even though it's already the 24th at UTC.

You'll need to polyfill Date.prototype.toISOString for it to work in Internet Explorer 8, but it should be supported everywhere else.

Maybe worth noting that it will only give you 2017-08-23 if you're sufficiently behind UTC (e.g. in the US). — Simon D, Sep 18 '17 at 08:40

Williaan Lopes · Answer 20 · 2020-04-29T03:36:09.897

4

new Date().toLocaleDateString('pt-br').split( '/' ).reverse( ).join( '-' );

or

new Date().toISOString().split('T')[0]
new Date('23/03/2020'.split('/').reverse().join('-')).toISOString()
new Date('23/03/2020'.split('/').reverse().join('-')).toISOString().split('T')[0]

Try this!

edited Apr 29 '20 at 03:36

answered Apr 24 '20 at 00:49

Williaan Lopes

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The second option might display the wrong date because it will display the data in UTC timezone. – Ever Dev May 08 '20 at 19:15

score 3 · Answer 21 · edited Oct 20 '17 at 05:56

3

Date.js is great for this.

require("datejs")
(new Date()).toString("yyyy-MM-dd")

edited Oct 20 '17 at 05:56

Pang

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answered Jun 09 '16 at 17:09

Tan Wang

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score 3 · Answer 22 · answered May 21 '20 at 11:09

3

If you use momentjs, now they include a constant for that format YYYY-MM-DD:

date.format(moment.HTML5_FMT.DATE)

answered May 21 '20 at 11:09

Stefan Zhelyazkov

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Gergo Erdosi · Answer 23 · 2014-05-11T13:29:13.517

2

Here is one way to do it:

var date = Date.parse('Sun May 11,2014');

function format(date) {
  date = new Date(date);

  var day = ('0' + date.getDate()).slice(-2);
  var month = ('0' + (date.getMonth() + 1)).slice(-2);
  var year = date.getFullYear();

  return year + '-' + month + '-' + day;
}

console.log(format(date));

edited May 11 '14 at 13:29

answered May 11 '14 at 13:23

Gergo Erdosi

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score 2 · Answer 24 · edited Sep 07 '19 at 13:48

Reformatting a date string is fairly straightforward, e.g.

var s = 'Sun May 11,2014';

function reformatDate(s) {
  function z(n){return ('0' + n).slice(-2)}
  var months = [,'jan','feb','mar','apr','may','jun',
                 'jul','aug','sep','oct','nov','dec'];
  var b = s.split(/\W+/);
  return b[3] + '-' +
    z(months.indexOf(b[1].substr(0,3).toLowerCase())) + '-' +
    z(b[2]);
}

console.log(reformatDate(s));

score 2 · Answer 25 · edited Sep 07 '19 at 12:58

A few of the previous answer were OK, but they weren't very flexible. I wanted something that could really handle more edge cases, so I took @orangleliu 's answer and expanded on it. https://jsfiddle.net/8904cmLd/1/

function DateToString(inDate, formatString) {
    // Written by m1m1k 2018-04-05

    // Validate that we're working with a date
    if(!isValidDate(inDate))
    {
        inDate = new Date(inDate);
    }

    // See the jsFiddle for extra code to be able to use DateToString('Sun May 11,2014', 'USA');
    //formatString = CountryCodeToDateFormat(formatString);

    var dateObject = {
        M: inDate.getMonth() + 1,
        d: inDate.getDate(),
        D: inDate.getDate(),
        h: inDate.getHours(),
        m: inDate.getMinutes(),
        s: inDate.getSeconds(),
        y: inDate.getFullYear(),
        Y: inDate.getFullYear()
    };

    // Build Regex Dynamically based on the list above.
    // It should end up with something like this: "/([Yy]+|M+|[Dd]+|h+|m+|s+)/g"
    var dateMatchRegex = joinObj(dateObject, "+|") + "+";
    var regEx = new RegExp(dateMatchRegex,"g");
    formatString = formatString.replace(regEx, function(formatToken) {
        var datePartValue = dateObject[formatToken.slice(-1)];
        var tokenLength = formatToken.length;

        // A conflict exists between specifying 'd' for no zero pad -> expand
        // to '10' and specifying yy for just two year digits '01' instead
        // of '2001'.  One expands, the other contracts.
        //
        // So Constrict Years but Expand All Else
        if (formatToken.indexOf('y') < 0 && formatToken.indexOf('Y') < 0)
        {
            // Expand single digit format token 'd' to
            // multi digit value '10' when needed
            var tokenLength = Math.max(formatToken.length, datePartValue.toString().length);
        }
        var zeroPad = (datePartValue.toString().length < formatToken.length ? "0".repeat(tokenLength) : "");
        return (zeroPad + datePartValue).slice(-tokenLength);
    });

    return formatString;
}

Example usage:

DateToString('Sun May 11,2014', 'MM/DD/yy');
DateToString('Sun May 11,2014', 'yyyy.MM.dd');
DateToString(new Date('Sun Dec 11,2014'),'yy-M-d');

Nice clean & commented solution. Yet I'm skeptical about the first argument, which is *silently* replaced by a fresh new date if not recognized as a valid date. I'd rather put this "optionnal default value" as 2nd argument instead, and return some kind of exception (could be a simple "Invalid date format" returned string) in case the format isn't recognized, so that error appear *clearly* to the tester/user — Balmipour, Oct 16 '19 at 10:04

score 2 · Answer 26 · answered Feb 28 '21 at 14:06

Unfortunately, JavaScript's Date object has many pitfalls. Any solution based on Date's builtin toISOString has to mess with the timezone, as discussed in some other answers to this question. The clean solution to represent an ISO-8601 date (without time) is given by Temporal.PlainDate from the Temporal proposal. As of February 2021, you have to choose the workaround that works best for you.

use `Date` with vanilla string concatenation

Assuming that your internal representation is based on Date, you can perform manual string concatenation. The following code avoids some of Date's pitfalls (timezone, zero-based month, missing 2-digit formatting), but there might be other issues.

function vanillaToDateOnlyIso8601() {
  // month May has zero-based index 4
  const date = new Date(2014, 4, 11);

  const yyyy = date.getFullYear();
  const mm = String(date.getMonth() + 1).padStart(2, "0"); // month is zero-based
  const dd = String(date.getDate()).padStart(2, "0");

  if (yyyy < 1583) {
    // TODO: decide how to support dates before 1583
    throw new Error(`dates before year 1583 are not supported`);
  }

  const formatted = `${yyyy}-${mm}-${dd}`;
  console.log("vanilla", formatted);
}

use `Date` with helper library (e.g. `formatISO` from `date-fns`)

This is a popular approach, but you are still forced to handle a calendar date as a Date, which represents

a single moment in time in a platform-independent format

The following code should get the job done, though:

import { formatISO } from "date-fns";

function dateFnsToDateOnlyIso8601() {
  // month May has zero-based index 4
  const date = new Date(2014, 4, 11);
  const formatted = formatISO(date, { representation: "date" });
  console.log("date-fns", formatted);
}

find a library that properly represents dates and times

I wish there was a clean and battle-tested library that brings its own well-designed date–time representations. A promising candidate for the task in this question was LocalDate from @js-joda/core, but the library is less active than, say, date-fns. When playing around with some example code, I also had some issues after adding the optional @js-joda/timezone.

However, the core functionality works and looks very clean to me:

import { LocalDate, Month } from "@js-joda/core";

function jodaDateOnlyIso8601() {
  const someDay = LocalDate.of(2014, Month.MAY, 11);
  const formatted = someDay.toString();
  console.log("joda", formatted);
}

experiment with the `Temporal`-proposal polyfill

This is not recommended for production, but you can import the future if you wish:

import { Temporal } from "proposal-temporal";

function temporalDateOnlyIso8601() {
  // yep, month is one-based here (as of Feb 2021)
  const plainDate = new Temporal.PlainDate(2014, 5, 11);
  const formatted = plainDate.toString();
  console.log("proposal-temporal", formatted);
}

score 1 · Answer 27 · answered Dec 19 '16 at 08:38

function myYmd(D){
    var pad = function(num) {
        var s = '0' + num;
        return s.substr(s.length - 2);
    }
    var Result = D.getFullYear() + '-' + pad((D.getMonth() + 1)) + '-' + pad(D.getDate());
    return Result;
}

var datemilli = new Date('Sun May 11,2014');
document.write(myYmd(datemilli));

score 1 · Answer 28 · edited Sep 07 '19 at 13:07

This worked for me to get the current date in the desired format (YYYYMMDD HH:MM:SS):

var d = new Date();

var date1 = d.getFullYear() + '' +
            ((d.getMonth()+1) < 10 ? "0" + (d.getMonth() + 1) : (d.getMonth() + 1)) +
            '' +
            (d.getDate() < 10 ? "0" + d.getDate() : d.getDate());

var time1 = (d.getHours() < 10 ? "0" + d.getHours() : d.getHours()) +
            ':' +
            (d.getMinutes() < 10 ? "0" + d.getMinutes() : d.getMinutes()) +
            ':' +
            (d.getSeconds() < 10 ? "0" + d.getSeconds() : d.getSeconds());

print(date1+' '+time1);

score 1 · Answer 29 · answered Jan 06 '19 at 10:24

var d = new Date("Sun May 1,2014");

var year  = d.getFullYear();
var month = d.getMonth() + 1;
var day   = d.getDate(); 

month = checkZero(month);             
day   = checkZero(day);

var date = "";

date += year;
date += "-";
date += month;
date += "-";
date += day;

document.querySelector("#display").innerHTML = date;
    
function checkZero(i) 
{
    if (i < 10) 
    {
        i = "0" + i
    };  // add zero in front of numbers < 10

    return i;
}

<div id="display"></div>

score 1 · Answer 30 · edited Mar 01 '19 at 05:39

1

new Date(new Date(YOUR_DATE.toISOString()).getTime() - 
                 (YOUR_DATE.getTimezoneOffset() * 60 * 1000)).toISOString().substr(0, 10)

edited Mar 01 '19 at 05:39

Uwe Keim

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answered Mar 01 '19 at 03:22

Lin

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score 1 · Answer 31 · edited Sep 07 '19 at 13:13

1

No library is needed

Just pure JavaScript.

The example below gets the last two months from today:

var d = new Date()
d.setMonth(d.getMonth() - 2);
var dateString = new Date(d);
console.log('Before Format', dateString, 'After format', dateString.toISOString().slice(0,10))

edited Sep 07 '19 at 13:13

Peter Mortensen

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answered Mar 15 '19 at 11:19

Panayiotis Georgiou

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1

Dangerous. In that case you ignore the timezone offset. – maxence51 Apr 18 '19 at 08:40

score 1 · Answer 32 · edited Sep 07 '19 at 13:14

PHP compatible date format

Here is a small function which can take the same parameters as the PHP function date() and return a date/time string in JavaScript.

Note that not all date() format options from PHP are supported. You can extend the parts object to create the missing format-token

/**
 * Date formatter with PHP "date()"-compatible format syntax.
 */
const formatDate = (format, date) => {
  if (!format) { format = 'Y-m-d' }
  if (!date) { date = new Date() }

  const parts = {
    Y: date.getFullYear().toString(),
    y: ('00' + (date.getYear() - 100)).toString().slice(-2),
    m: ('0' + (date.getMonth() + 1)).toString().slice(-2),
    n: (date.getMonth() + 1).toString(),
    d: ('0' + date.getDate()).toString().slice(-2),
    j: date.getDate().toString(),
    H: ('0' + date.getHours()).toString().slice(-2),
    G: date.getHours().toString(),
    i: ('0' + date.getMinutes()).toString().slice(-2),
    s: ('0' + date.getSeconds()).toString().slice(-2)
  }

  const modifiers = Object.keys(parts).join('')
  const reDate = new RegExp('(?<!\\\\)[' + modifiers + ']', 'g')
  const reEscape = new RegExp('\\\\([' + modifiers + '])', 'g')

  return format
    .replace(reDate, $0 => parts[$0])
    .replace(reEscape, ($0, $1) => $1)
}

// ----- EXAMPLES -----
console.log( formatDate() ); // "2019-05-21"
console.log( formatDate('H:i:s') ); // "16:21:32"
console.log( formatDate('Y-m-d, o\\n H:i:s') ); // "2019-05-21, on 16:21:32"
console.log( formatDate('Y-m-d', new Date(2000000000000)) ); // "2033-05-18"

Gist

Here is a gist with an updated version of the formatDate() function and additional examples: https://gist.github.com/stracker-phil/c7b68ea0b1d5bbb97af0a6a3dc66e0d9

score 1 · Answer 33 · answered May 26 '21 at 09:46

1

Easy way to do this issue

console.log((new Date()).toDateString("YYYY-MM-DD"))

answered May 26 '21 at 09:46

Willie Cheng

5,589
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score 0 · Answer 34 · edited Sep 07 '19 at 12:45

0

If the date needs to be the same across all time zones, for example represents some value from the database, then be sure to use UTC versions of the day, month, fullyear functions on the JavaScript date object as this will display in UTC time and avoid off-by-one errors in certain time zones.

Even better, use the Moment.js date library for this sort of formatting.

edited Sep 07 '19 at 12:45

Peter Mortensen

28,342
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answered May 11 '14 at 14:45

GameSalutes

1,392
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score 0 · Answer 35 · answered Aug 22 '17 at 15:43

Yet another combination of the answers. Nicely readable, but a little lengthy.

function getCurrentDayTimestamp() {
  const d = new Date();

  return new Date(
    Date.UTC(
      d.getFullYear(),
      d.getMonth(),
      d.getDate(),
      d.getHours(),
      d.getMinutes(),
      d.getSeconds()
    )
  // `toIsoString` returns something like "2017-08-22T08:32:32.847Z"
  // and we want the first part ("2017-08-22")
  ).toISOString().slice(0, 10);
}

score 0 · Answer 36 · edited Sep 07 '19 at 12:52

0

I modified Samit Satpute's response as follows:

var newstartDate = new Date();
// newstartDate.setDate(newstartDate.getDate() - 1);
var startDate = newstartDate.toISOString().replace(/[-T:\.Z]/g, ""); //.slice(0, 10); // To get the Yesterday's Date in YYYY MM DD Format
console.log(startDate);

edited Sep 07 '19 at 12:52

Peter Mortensen

28,342
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answered Oct 04 '17 at 15:46

suleman

70
5

score 0 · Answer 37 · edited Sep 07 '19 at 13:09

Format and finding maximum and minimum date from hashmap data:

var obj = {"a":'2001-15-01', "b": '2001-12-02' , "c": '2001-1-03'};

function findMaxMinDate(obj){
  let formatEncode = (id)=> { let s = id.split('-'); return `${s[0]+'-'+s[2]+'-'+s[1]}`}
  let formatDecode = (id)=> { let s = id.split('/'); return `${s[2]+'-'+s[0]+'-'+s[1]}`}
  let arr = Object.keys( obj ).map(( key )=> { return new Date(formatEncode(obj[key])); });
  let min = new Date(Math.min.apply(null, arr)).toLocaleDateString();
  let max = new Date(Math.max.apply(null, arr)).toLocaleDateString();
  return {maxd: `${formatDecode(max)}`, mind:`${formatDecode(min)}`}
}

console.log(findMaxMinDate(obj));

How is this related to the question (formatting a date)? – Peter Mortensen Sep 07 '19 at 13:10 — Peter Mortensen, Sep 07 '19 at 13:10

score 0 · Answer 38 · edited Mar 05 '20 at 23:18

This code change the order of DD MM YYYY

function convertDate(format, date) {
    let formatArray = format.split('/');
    if (formatArray.length != 3) {
        console.error('Use a valid Date format');
        return;
    }
    function getType(type) { return type == 'DD' ? d.getDate() : type == 'MM' ? d.getMonth() + 1 : type == 'YYYY' && d.getFullYear(); }
    function pad(s) { return (s < 10) ? '0' + s : s; }
    var d = new Date(date);
    return [pad(getType(formatArray[0])), pad(getType(formatArray[1])), getType(formatArray[2])].join('/');
}

score 0 · Answer 39 · answered May 02 '20 at 02:53

const today = new Date(); // or whatever 

const yearFirstFormater = (date): string => {
    const modifiedDate = new Date(date).toISOString().slice(0, 10);
    return `${modifiedDate.split('-')[0]}/${modifiedDate.split('-')[1]}/${modifiedDate.split('-')[2]}`;
}

const monthFirstFormater = (date): string => {
    const modifiedDate = new Date(date).toISOString().slice(0, 10);
    return `${modifiedDate.split('-')[1]}/${modifiedDate.split('-')[2]}/${modifiedDate.split('-')[0]}`;
}

const dayFirstFormater = (date): string => {
    const modifiedDate = new Date(date).toISOString().slice(0, 10);
    return `${modifiedDate.split('-')[2]}/${modifiedDate.split('-')[1]}/${modifiedDate.split('-')[0]}`;
}

console.log(yearFirstFormater(today));
console.log(monthFirstFormater(today));
console.log(dayFirstFormater(today));

score 0 · Answer 40 · answered Sep 10 '20 at 07:04

formatDate(date) {
  const d = new Date(date)
  const ye = new Intl.DateTimeFormat('en', { year: 'numeric' }).format(d);
  const mo = new Intl.DateTimeFormat('en', { month: 'short' }).format(d);
  const da = new Intl.DateTimeFormat('en', { day: '2-digit' }).format(d);
  return `${da}-${mo}-${ye}`;
}

console.log("Formatated Date : ", formatDate("09/25/2020") )
// Output :: Formatated Date : 25-Sep-2020

score 0 · Answer 41 · answered Mar 24 '21 at 09:24

Follow up on https://stackoverflow.com/a/29774197/1189762 This is what I had to change regarding the offset for when people are east or west from the Greenwich Mean Time:

export const toNativeHtml5InputDate = (date) => {
  if (!date) return date;

  let offset = new Date(date).getTimezoneOffset();

  offset =
    offset < 0
      ? offset * -1 // east from Greenwich Mean Time
      : offset; // west from Greenwich Mean Time

  return new Date(new Date(date).getTime() + offset * 60 * 1000)
    .toISOString()
    .split('T')[0];
};

score -1 · Answer 42 · edited Oct 20 '17 at 05:57

All given answers are great and helped me big. In my situation, I wanted to get the current date in yyyy mm dd format along with date-1. Here is what worked for me.

var endDate = new Date().toISOString().slice(0, 10); // To get the Current Date in YYYY MM DD Format

var newstartDate = new Date();
newstartDate.setDate(newstartDate.getDate() - 1);
var startDate = newstartDate.toISOString().slice(0, 10); // To get the Yesterday's Date in YYYY MM DD Format
alert(startDate);

score -3 · Answer 43 · edited Sep 07 '19 at 12:53

-3

It is easily accomplished by my date-shortcode package:

const dateShortcode = require('date-shortcode')
dateShortcode.parse('{YYYY-MM-DD}', 'Sun May 11,2014')
//=> '2014-05-11'

edited Sep 07 '19 at 12:53

Peter Mortensen

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answered Mar 04 '18 at 18:55

Kodie Grantham

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I really don't get the downvotes. This is definitely a way to accomplish what OP was asking. – Kodie Grantham Aug 26 '19 at 14:05

dipser · Answer 44 · 2020-08-26T09:04:15.990

We run constantly into problems like this. Every solution looks so individual. But looking at php, we have a way dealing with different formats. And there is a port of php's strtotime function at https://locutus.io/php/datetime/strtotime/. A small open source npm package from me as an alternative way:

<script type="module">
import { datebob } from "@dipser/datebob.js";
console.log( datebob('Sun May 11, 2014').format('Y-m-d') ); 
</script>

See datebob.js

score -6 · Answer 45 · edited Sep 07 '19 at 13:43

This worked for me, and you can paste this directly into your HTML if needed for testing:

<script type="text/javascript">
    if (datefield.type!="date"){ // If the browser doesn't support input type="date",
                                 // initialize date picker widget:
        jQuery(function($){ // On document.ready
            $('#Date').datepicker({
                dateFormat: 'yy-mm-dd', // THIS IS THE IMPORTANT PART!!!
                showOtherMonths: true,
                selectOtherMonths: true,
                changeMonth: true,
                minDate: '2016-10-19',
                maxDate: '2016-11-03'
            });
        })
    }
</script>

Format JavaScript date as yyyy-mm-dd

45 Answers45

Demo

Result:

Shortest

use `Date` with vanilla string concatenation

use `Date` with helper library (e.g. `formatISO` from `date-fns`)

find a library that properly represents dates and times

experiment with the `Temporal`-proposal polyfill

PHP compatible date format

Linked

Related

Format JavaScript date as yyyy-mm-dd

45 Answers45

Demo

Result:

Shortest

use Date with vanilla string concatenation

use Date with helper library (e.g. formatISO from date-fns)

find a library that properly represents dates and times

experiment with the Temporal-proposal polyfill

PHP compatible date format

Linked

Related

use `Date` with vanilla string concatenation

use `Date` with helper library (e.g. `formatISO` from `date-fns`)

experiment with the `Temporal`-proposal polyfill