Regex Pattern matching for an URL

Question

I have a method and input to that is an URL string. I would different types of URL (sample 5 URLs i have mentioned below)

String url1 = "http://domainName/contentid/controller_hscc.jsp?q=1" ;
String url2 = "http://domainName/contentid/controller.jsp?waitage=1" ;
String url3 = "http://domainName/contentid/controller_runner.jsp" ;
String url4 = "http://domainName/contentid/jump.jsp?q=5" ;
String url5 = "http://domainName/contentid/jump.jsp" ;

I need to find if this URL has controller*.jsp pattern in it. If so, I will have to write some other logic for it.

Now, I need to know how to write * controller*.jsp pattern in java

I wrote a regex this way and it returns false always

boolean retVal = Pattern.matches("^(controller)*", url) ;

PS : I use JDK1.4

EDIT-1

I tried below way. Still not woring

import java.util.regex.Matcher;
import java.util.regex.Pattern;
public class HelloWorld{

     public static void main(String []args){
        String url = "http://domainName/contentid/controller_hscc.jsp?q=1" ;
        //String url = "baaaaab" ;
        String regex = "/controller(\\w+)?\\.jsp*" ;

        Pattern p = Pattern.compile(regex);
        Matcher m = p.matcher(url);
        System.out.println(m.matches());
     }
}

FYI: Here are two answers from the [Stack Overflow Regular Expressions FAQ](http://stackoverflow.com/a/22944075/2736496) that relate to your question: [validating urls](http://stackoverflow.com/a/190405/2736496) and [validating urls with host/port](http://stackoverflow.com/a/22697740/578411). Both are listed under "Common Validation Tasks". — aliteralmind, Apr 25 '14 at 12:13

score 2 · Answer 1 · answered Apr 25 '14 at 08:33

2

Match it against the following regex:

controller(\w+)?\.jsp

Demo

answered Apr 25 '14 at 08:33

sshashank124

28,066
8
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@Arun, Are you sure. Because As you can see from my Demo, it _does_ work – sshashank124 Apr 25 '14 at 09:48
no sashank, its not working, can you copy-paste my code and test here http://www.compileonline.com/compile_java_online.php – Arun Apr 25 '14 at 09:50
@Arun, Try this instead: `.*?controller(\w+)?\.jsp.*?` – sshashank124 Apr 25 '14 at 09:55
@Arun, Sorry, I meant this: `^.*?controller(\w+)?\.jsp.*?$` – sshashank124 Apr 25 '14 at 09:55
getting compilation exception in java .. String pattern = ".*?controller(\w+)?\.jsp.*?" ; – Arun Apr 25 '14 at 09:59
sashank. still get compilation issue :( – Arun Apr 25 '14 at 10:03

score 1 · Answer 2 · answered Apr 25 '14 at 08:41

1

String re = "controller.+jsp";
String str = "http://domainName/contentid/controller_hscc.jsp?q=1";

Pattern p = Pattern.compile(re);
Matcher m = p.matcher(str);

answered Apr 25 '14 at 08:41

Sirius_Black

444
3
11

score 1 · Accepted Answer · answered Apr 25 '14 at 10:03

Try this code:

import java.util.regex.Matcher;
import java.util.regex.Pattern;
public class HelloWorld{

     public static void main(String []args){
        String url = "http://domainName/contentid/controller_hscc.jsp?q=1" ;
        //String url = "baaaaab" ;
        String regex = "^.*?controller(\\w+)?\\.jsp.*?$" ;

        Pattern p = Pattern.compile(regex);
        Matcher m = p.matcher(url);
        boolean retVal = Pattern.matches(regex, url) ;
        System.out.println(m.matches() + "__" + retVal);
     }
}

Sufian Latif · Answer 4 · 2014-04-25T10:14:23.867

1

I found this working fine:

(controller.*\.jsp(\?.*)?)

see here.

As a java string, it should be "(controller.*\\.jsp(\\?.*)?)"

Moreover, it will give you two groups: the whole one and the part after the ?.

You could also do it by splitting the url by /s, taking the last part and checking if that starts with controller - without using any regex.

edited Apr 25 '14 at 10:14

answered Apr 25 '14 at 10:07

Sufian Latif

12,106
3
31
68

Regex Pattern matching for an URL

4 Answers4

Demo