I want to round float to a given precision. For example:
0,6667 to 0,67
0,004 to 0,00
0,328 to 0,33
I know I can round a float to integer, for example:
0,06 to 0
Is there any way to achieve this?
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Oleksandr Firsov
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Try using the solution found here http://stackoverflow.com/questions/153724/how-to-round-a-number-to-n-decimal-places-in-java?rq=1 – Dan Harms Apr 12 '14 at 15:17
2 Answers
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Format a floating point number to a string with a specified number of decimal places using String.format(...).
Example:
String.format("%.2f", myFloatingPointValue);
Hidde
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Do you need the rounding for display or for calculations?
If it's for display you can use this:
DecimalFormat df = new DecimalFormat("##.00");
float f = (float) 4.234432;
System.out.println(df.format(f));
For calculations, you could do it like this:
float f = (float) 4.234432;
BigDecimal bd = new BigDecimal(f);
bd = bd.setScale(2, RoundingMode.HALF_UP);
f = bd.floatValue();
wvdz
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for display, but I would like to know how to do it for calculations – Oleksandr Firsov Apr 12 '14 at 15:22
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Added that one as well. Both methods are quite verbose, but well... it gets it done. – wvdz Apr 12 '14 at 15:29