how to use regex to beautifully dissect urls

Question

I want to use regex to get an arrayLike object from the params giving to url

e.g.

http://mysite/myPeople?one=jose&two=emily&three=john

basically what it does is this

    function interpretUrl(url){

        var reg = /\?([^&?=]*)=([^&?=]*)/g; //what am i doing wrong?

        //some logic here
        reg.exec(url)

        return {
            param: [
                one: 'jose',
                two: 'emily',
                three: 'john'
            ],
            root:
        }
    }

This is answered in the [Stack Overflow Regular Expressions FAQ](http://stackoverflow.com/a/22944075/2736496), both listed under "Common Validation Tasks": [matching urls](http://stackoverflow.com/a/190405/2736496) and [matching host/port](http://stackoverflow.com/a/22697740/578411) — aliteralmind, Apr 11 '14 at 16:54

score 1 · Accepted Answer · answered Apr 11 '14 at 16:55

1

You can use this to get all the parameters from query string:

var re = /([^?&]+)=([^&]*)/g,
    matches = {},
    input = "http://mysite/myPeople?one=jose&two=emily&three=john";
while (match = re.exec(input.substr(input.indexOf('?')+1))) matches[match[1]] = match[2];

console.log(matches);
//=> {one: "jose", two: "emily", three: "john"}

answered Apr 11 '14 at 16:55

anubhava

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thanks, is there a way to do it more than once without the loop? what was I doing wrong? – user2167582 Apr 11 '14 at 17:06
I don't think loop can be avoided here due to use of `/g` flag in `exec`. Javascript doesn't have equivalent of PHP's `preg_match_all`. – anubhava Apr 11 '14 at 17:08
whats the use of the /g and is it possible to matchall without adding it? – user2167582 Apr 11 '14 at 17:18
`g` is for global to find all the matches. Without `g` it will only find first pair instead of all. – anubhava Apr 11 '14 at 17:31
but looks like even so it will stop on the first pair it finds? – user2167582 Apr 23 '14 at 06:45
Just copy paste above code and test it. I also provided you output. – anubhava Apr 23 '14 at 06:49

how to use regex to beautifully dissect urls

1 Answers1