Entire question :
Question 3
You are the owner of a hardware store and need to keep an inventory that can tell you what different tools you have, how many of each you have on hand and the cost of each one. Write a program that initializes the random-access file "hardware.dat" to 100 empty records, let you input the data concerning each tool, enables you to list all your tools, lets you delete a record for a tool that you no longer have and lets you update any information in the file. The tool identification number should be the record number. Use the following information to start your file.
My Code :
int question_3()
{
cout << "Question 3" << endl;
fstream hardware;
hardware.open("hardware.dat" , ios::binary | ios::out);
//Create 100 blank objects---------------------------------------------------------------
if (!hardware)
{
cerr << "File could not be opened." << endl;
exit(1);
}
HardwareData myHardwareData;
for (int counter = 1; counter <= 100; counter++)
{
hardware.write(reinterpret_cast< const char * >(&myHardwareData), sizeof(HardwareData));
}
cout << "Successfully create 100 blank objects and write them into the file." << endl;
hardware.close();
hardware.open("hardware.dat" , ios::binary | ios::out | ios::in);
//Write data-----------------------------------------------------------------------------
int record;
int quantity;
float cost;
string tool_name;
cout << endl;
cout << "Enter record number (1 to 100, 0 to end input) : ";
cin >> record;
while (record != 0)
{
cin.sync();
cout << "Enter tool name : "; getline(cin, tool_name);
cout << "Enter quantity : "; cin >> quantity;
cout << "Enter cost : "; cin >> cost;
myHardwareData.setRecord(record);
myHardwareData.setToolName(tool_name);
myHardwareData.setQuantity(quantity);
myHardwareData.setCost(cost);
hardware.seekp((myHardwareData.getRecord() - 1) * sizeof(HardwareData));
hardware.write(reinterpret_cast<const char *>(&myHardwareData), sizeof(HardwareData));
cout << endl
<< "Enter record number (1 to 100, 0 to end input) : ";
cin >> record;
}
cout << "Successfully write all input data into the file." << endl;
//Read data----------------------------------------------------------------------------
cout << endl;
outputDataLineHead();
hardware.read(reinterpret_cast<char *>(&myHardwareData), sizeof(HardwareData));
int counter = 0;
cout << setprecision(2) << fixed;
while (hardware && !hardware.eof())
{
if (myHardwareData.getRecord() != 0)
outputDataLine(cout, myHardwareData);
hardware.seekp(counter++ * sizeof(HardwareData));
hardware.read(reinterpret_cast<char *>(&myHardwareData), sizeof(HardwareData));
}
return 0;
}
//Function for showing data in line form.-----------------------------------------------
void outputDataLineHead()
{
cout << left << setw(17) << "Record No."
<< left << setw(17) << "Tool Name"
<< left << setw(17) << "Quantity"
<< left << setw(17) << "Cost" << endl;
}
void outputDataLine(ostream &output, const HardwareData &Object_in_file)
{
output << left << setw(17) << Object_in_file.getRecord()
<< left << setw(17) << Object_in_file.getToolName()
<< left << setw(17) << Object_in_file.getQuantity()
<< left << setw(17) << Object_in_file.getCost() << endl;
}
HardwareData.h :
#ifndef HAREWAREDATA_H
#define HAREWAREDATA_H
#include <iostream>
using std::string;
class HardwareData
{
public :
HardwareData(string name = "", int recd = 0, int qutity = 0, float cot = 0.0)
{
setToolName(name);
setRecord(recd);
setQuantity(qutity);
setCost(cot);
}
void setToolName(string name)
{
const char *nameValue = name.data();
int length = 0;
length = (length < 15 ? length : 14);
strncpy(tool_name, nameValue, length);
tool_name[length] = '\n';
}
string getToolName() const
{
return tool_name;
}
void setRecord(int recd)
{
record = recd;
}
int getRecord() const
{
return record;
}
void setQuantity(int qutity)
{
quantity = qutity;
}
int getQuantity() const
{
return quantity;
}
void setCost(float cot)
{
cost = cot;
}
float getCost() const
{
return cost;
}
private :
char tool_name[15];
int record;
int quantity;
float cost;
};
#endif
I want to show the data like the following :
Record No. Tool Name Quantity Cost
4 electric hammer 3 34.32
How to achieve this?
Thank you for your attention.