Remove part of string in PHP

Question

How can i replace unused section in content. For example:

$content = "
    Test content

    [section]
        Section Content
    [section]

    End.
";

$content = preg_replace('/\[section\](.*)\[section\]/', '', $content);

Thanks

add the `s` modifier to match newlines with `.`. Also don't forget to make your expression [ungreedy](http://stackoverflow.com/questions/3075130/difference-between-and-for-regex) `/\[section\](.*?)\[section\]/s` — HamZa, Nov 23 '13 at 22:10

hwnd · Accepted Answer · 2013-11-24T00:03:55.513

3

The s modifier allows a dot metacharacter in the pattern to match all characters, including newlines.

The i modifier is used for case-insensitive matching allowing both upper and lower case letters. By adding the quantifier ? it makes for a non greedy match and matches the least amount possible.

$content = preg_replace('/\[section\].*?\[section\]/si', '', $content);

See Demo

edited Nov 24 '13 at 00:03

answered Nov 23 '13 at 22:19

hwnd

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@adoweb If this worked, its nice to accept an answer and close the question. – hwnd Nov 25 '13 at 14:34

score 2 · Answer 2 · answered Nov 24 '13 at 00:08

2

What's the regex for? This should work and will run a lot quicker:

$content = explode('[section]',$content);
$content = $content[0].$content[2];

answered Nov 24 '13 at 00:08

cronoklee

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Remove part of string in PHP

2 Answers2