I have a class Samp. In Samp.cpp, I can define/declare a function like
Samp& operator+(Samp& other) {
std::cout << "something";
return other;
}
What is this function exactly? How do I call it?
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Daniel Frey
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shreyasva
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http://stackoverflow.com/questions/4622330/operator-overloading-member-function-vs-non-member-function – Gabriel L. Oct 10 '13 at 20:58
1 Answers
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This is actually a unary +, you call it like this:
Samp s;
+s; // <-- here
Daniel Frey
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2@buc Wat? Of course C++ has unary `+`. Want some fun with unary `+`? Check [this](http://stackoverflow.com/questions/18889028) out :) – Daniel Frey Oct 10 '13 at 21:02
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Well, it could be binary member `operator+` - but the fact that it returns reference kind of makes it wrong, but it's wrong anyway because of unclear semantics. – milleniumbug Oct 10 '13 at 21:02
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@DanielFrey: That's brilliant. It hadn't occurred to me that that would be a free function. – Kerrek SB Oct 10 '13 at 21:02
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Unless this is defined within the class declaration, then it is the addition operator. – Zac Howland Oct 10 '13 at 21:04
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2+1, unary makes much more sense than binary, since it is returning a reference. – juanchopanza Oct 10 '13 at 21:04
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@ZacHowland In that case it most probably won't go into the `.cpp` file. – Daniel Frey Oct 10 '13 at 21:04
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