How to filter out numbers from a string in java?

Question

I have a string of the following form for instance -:

String str = "The game received average review scores of 96.92% and 98/100 for the Xbox 360 version";

and I want the output as follows -:

Output = "The game received average review scores of % and / for the Xbox version"

and I want to be able to filter out any number that's there in the string whether its a decimal or a floating point number, I tried using a brute force way of doing this like this -:

String str = "The game received average review scores of 96.92% and 98/100 for the Xbox 360 version";

String newStr = "";

for(int i = 0 ; i < str.length() ; ++i){
if(!Character.isDigit(str.charAt(i)))
   newStr += str.charAt(i);
}

System.out.println(newStr);

but this doesn't solve the purpose for me, how to go about solving this problem?

You might check out [this answer](http://stackoverflow.com/a/19169192/1578604) which is basically the opposite of what you're looking for. With some tweaking, you can use it. — Jerry, Oct 04 '13 at 20:50

anubhava · Answer 1 · 2013-10-04T20:49:21.680

2

You can use following String#replaceAll call to replace all numbers (followed by 0 or more spaces) by an empty string:

str.replaceAll("\\d+(,\\d+)*(?:\\.\\d+)?\\s*", "");

edited Oct 04 '13 at 20:49

answered Oct 04 '13 at 20:47

anubhava

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this doesn't work for such kind of string : "The App Store offered more than 775,000 apps by Apple and third parties." it leaves a "," in between – AnkitSablok Oct 04 '13 at 20:50
You example also has `%` and `/` left behind in the string. – anubhava Oct 04 '13 at 20:52

score 1 · Accepted Answer · answered Oct 04 '13 at 20:52

1

You can perhaps use something like this:

str.replaceAll("\\d+(?:[.,]\\d+)*\\s*", "");

answered Oct 04 '13 at 20:52

Jerry

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How to filter out numbers from a string in java?

2 Answers2