i am trying to display an image in HTML using:
<img src="/logo.php?seq=5" />
then logo.php looks like:
<?php
$sql="SELECT * from reseller where sequence = '".$_GET["seq"]."' ";
$rs=mysql_query($sql,$conn);
$result=mysql_fetch_array($rs);
echo '<img src="http://www.integradigital.co.uk/customer/'.$result["logo"].'" />';
?>
but its not working - whats the best way to do this so the user seeing the image cannot look at the URL of the image. if they open the image in its own window i want them to see something like http://www.domain.com/logo.php?seq=5 ???