Python - Count number of words in a list strings

Question

Im trying to find the number of whole words in a list of strings, heres the list

mylist = ["Mahon Point retail park", "Finglas","Blackpool Mahon", "mahon point  blanchardstown"]

expected outcome:

There are 4 words in mylist[0], 1 in mylist[1] and so on

for x, word in enumerate(mylist):
    for i, subwords in enumerate(word):
        print i

Totally doesnt work....

What do you guys think?

possible duplicate of [Count word occurrence in a list of strings](http://stackoverflow.com/questions/18231542/count-word-occurrence-in-a-list-of-strings) — Viktor Kerkez, Sep 16 '13 at 11:47

score 19 · Accepted Answer · answered Sep 16 '13 at 11:50

19

Use str.split:

>>> mylist = ["Mahon Point retail park", "Finglas","Blackpool Mahon", "mahon point  blanchardstown"] 
>>> for item in mylist:
...     print len(item.split())
...     
4
1
2
3

answered Sep 16 '13 at 11:50

Ashwini Chaudhary

217,951
48
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461

score 4 · Answer 2 · answered Sep 16 '13 at 11:50

4

The simplest way should be

num_words = [len(sentence.split()) for sentence in mylist]

answered Sep 16 '13 at 11:50

Hari Menon

29,411
12
76
104

score 2 · Answer 3 · answered Aug 11 '15 at 23:58

2

You can use NLTK:

import nltk
mylist = ["Mahon Point retail park", "Finglas","Blackpool Mahon", "mahon point  blanchardstown"]
print(map(len, map(nltk.word_tokenize, mylist)))

Output:

[4, 1, 2, 3]

answered Aug 11 '15 at 23:58

Franck Dernoncourt

62,576
61
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score 0 · Answer 4 · answered Sep 16 '13 at 12:12

0

for x,word in enumerate(mylist):
    print len(word.split())

answered Sep 16 '13 at 12:12

Srinivasreddy Jakkireddy

2,083
1
9
7

score 0 · Answer 5 · edited Sep 13 '16 at 12:02

0

a="hello world aa aa aa abcd  hello double int float float hello"
words=a.split(" ")
words
dic={}
for word in words:
    if dic.has_key(word):
        dic[word]=dic[word]+1
    else:
        dic[word]=1
dic

edited Sep 13 '16 at 12:02

iScrE4m

865
1
10
28

answered Sep 13 '16 at 10:30

Usama Chitapure

1

1

Please format you code and explain what additional value your answer brings to other answers – Andrejs Sep 13 '16 at 10:56
If you want to count unique words you can use sets. Simply it is `len(set(a.split()))` – Mohammad ElNesr Jan 11 '18 at 05:07

score 0 · Answer 6 · edited May 16 '19 at 02:56

0

We can count the number of a word's ocurrence in a list using the Counter function.

from collection import Counter

string = ["mahesh","hello","nepal","nikesh","mahesh","nikesh"]

count_each_word = Counter(string)
print(count_each_word)

Output:

Counter({mahesh:2},{hello:1},{nepal:1},{nikesh:2})

edited May 16 '19 at 02:56

Hoppeduppeanut

933
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answered May 16 '19 at 01:31

Mahesh Acharya

1
1

score 0 · Answer 7 · answered Aug 26 '19 at 16:38

This is another solution:

You can clean your data first and then count the result, something like that:

mylist = ["Mahon Point retail park", "Finglas","Blackpool Mahon", "mahon point  blanchardstown"] 
for item in mylist:
    for char in "-.,":
        item = item.replace(char, '')
        item_word_list = item.split()
    print(len(item_word_list))

The result:

score 0 · Answer 8 · answered Mar 11 '20 at 19:55

mylist = ["Mahon Point retail park", "Finglas","Blackpool Mahon", "mahon point blanchardstown"]
flage = True
for string1 in mylist:
    n = 0
    for s in range(len(string1)):
        if string1[s] == ' ' and flage == False:
            n+=1
        if string1[s] == ' ':
            flage = True
        else:
            flage = False
    print(n+1)

Python - Count number of words in a list strings

8 Answers8

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