Beginner with 'nextLine'

Question

I am working on a java problem at the moment where I am creating a program that simulates the old TV quiz show, You Bet Your Life. The game show host, Groucho Marx, chooses a secret word, then chats with the contestants for a while. If either contestant uses the secret word in a sentence, he or she wins $100.00.

My program is meant to check for this secret word.

Here is my code so far:

import java.util.Scanner; 

public class Groucho {
  String secret; 

  Groucho(String secret) {
     this.secret = secret; 
  }

  public String saysSecret(String line) {
     if(secret.equals(line)){
         return ("true");
     } else {
         return ("false");
     }
  }

  public static void main(String[] args){
     Scanner in = new Scanner(System.in); 
  }

}

In the main method I need to now create a new Groucho object with a secret word from the first line of standard input (in.nextLine()).

I am not sure how I go about doing this? Can someone explain please! Thanks! Miles

Try http://stackoverflow.com/questions/5032356/using-scanner-nextline — newuser, Sep 10 '13 at 14:33
Scanner Detailed explanation http://www.java-made-easy.com/java-scanner.html — newuser, Sep 10 '13 at 14:36

score 2 · Answer 1 · answered Sep 10 '13 at 14:34

2

Have a look at the Scanner API, and perhaps the Java Tutorial on Objects. And that on Strings.

Learning the basics is usually more useful than just getting a line of code from somewhere.

No offence :).

answered Sep 10 '13 at 14:34

s.d

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+1 for `Learning the basics is usually more useful than just getting a line of code from somewhere.` – Konstantin Yovkov Sep 10 '13 at 14:38

Konstantin Yovkov · Answer 2 · 2013-09-10T14:46:47.997

1

You can read the line with the following statement:

String line = in.nextLine();

Then, if you'd like to have the first word (for example), you can split the line and create a new Groucho object.

String split = line.split(" ");
Groucho g = new Groucho(split[0]);

Here you can find more information about :

edited Sep 10 '13 at 14:46

answered Sep 10 '13 at 14:32

Konstantin Yovkov

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When I try that is says: cannot find symbol symbol : method readLine() – Miles Roberts Sep 10 '13 at 14:36
Don't you have to declare `split` as a `String []`, not just a `String`? – AJMansfield Sep 10 '13 at 14:50
It has to be a `String[]`, because the `.split()` method returns an array of `String` objects. – Konstantin Yovkov Sep 10 '13 at 14:53

score 0 · Answer 3 · answered Apr 03 '14 at 19:49

0

You would create a new Groucho object and pass in in.nextLine() as a parameter. This would be done by Groucho g = new Groucho( in.nextLine() );

answered Apr 03 '14 at 19:49

Sman25

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10
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score 0 · Answer 4 · answered Apr 06 '14 at 03:04

0

You will need something that looks like this:

Scanner in = new Scanner(System.in); //take in word

String secretWord = in.nextLine(); //put it in a string

Groucho host = new Groucho (secretWord); //create a Groucho object and pass it the word

answered Apr 06 '14 at 03:04

user3033596

1

score 0 · Answer 5 · answered Apr 22 '14 at 13:14

0

in.nextLine() will take a single line of the whole input, so you can simply pass it into the constructor.

For example:

String inputWord = in.nextLine();
Groucho g = new Groucho(inputWord);

answered Apr 22 '14 at 13:14

mashaned

93
11

Shruti · Answer 6 · 2014-11-01T03:11:20.587

In the Scanner class the nextLine() method takes the next line of input as a String. You can save that line of input to a String variable:

String line = in.nextLine();

Now that you have a full line of input, you can get the first word from it.

In a sentence each word is separated from other words by a space. In the String class the split() method can split a String into an array of smaller strings, such as words in a sentence, with a given separator, such as a space (" "), that you specify as a parameter:

String[] words = line.split(" ");

Next you can choose a secret word from the array by selecting the appropriate index.

For the first word:

String chosenWord = words[1];

For the last word:

String chosenWord = words[words.length - 1];

For a random word:

String chosenWord = words[Math.floor(Math.random() * words.length)];

Now you can simply pass on the secret word as a parameter to a new Groucho constructor:

Groucho secretWord = new Groucho(chosenWord);

This step by step explanation created a new variable at each step. You can accomplish the same task by combining multiple lines of code into a single statement and avoid creating unnecessary variables.

Beginner with 'nextLine'

6 Answers6