Running an outside program (executable) in Python?

Question

I just started working on Python, and I have been trying to run an outside executable from Python.

I have an executable for a program written in Fortran. Let’s say the name for the executable is flow.exe. And my executable is located in C:\Documents and Settings\flow_model. I tried both os.system and popen commands, but so far I couldn't make it work. The following code seems like it opens the command window, but it wouldn't execute the model.

# Import system modules
import sys, string, os, arcgisscripting
os.system("C:/Documents and Settings/flow_model/flow.exe")

How can I fix this?

Possible duplicate of [Calling an external command in Python](https://stackoverflow.com/questions/89228/calling-an-external-command-in-python) — mkobit, Nov 06 '17 at 16:42

score 46 · Accepted Answer · edited Feb 08 '21 at 15:32

46

Those whitespaces can really be a bother. Try os.chdir('C:/Documents\ and\ Settings/') followed by relative paths for os.system, subprocess methods, or whatever...

If best-effort attempts to bypass the whitespaces-in-path hurdle keep failing, then my next best suggestion is to avoid having blanks in your crucial paths. Couldn't you make a blanks-less directory, copy the crucial .exe file there, and try that? Are those havoc-wrecking space absolutely essential to your well-being...?

edited Feb 08 '21 at 15:32

Neuron

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answered Nov 28 '09 at 06:08

Alex Martelli

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Alex, thanks. This worked too. I have one more question if you dont mind. How about if my executable is asking for the name of my input file? I tried to do it using stdin but couldn't succeed so far? – Mesut Nov 29 '09 at 03:19
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@mesut, what's that executable using to "ask for" the filename? If it's its own standard-input, for example, you might be able to use `subprocess.Popen` to pipe your desired values there. If it goes deeper (using "console" input), try wexpect, http://sage.math.washington.edu/home/goreckc/sage/wexpect/ . – Alex Martelli Nov 29 '09 at 04:01
the input file is a basic .txt file in the same folder. The code right now opens the exe from the cmd window. And the executable asks for the name of the input file. Is there a way that I can just define this name (maybe as a path) within the code? I tried subprocess.popen and I tried to look in the variables. I thought that I can use stdin but didnt really work out. I would really appreciate if you can give me a sample with subprocess.popen with the executable located in C:\flow_model, the name of the executable as flow.exe and name of the input file located in the same folder as sac_bsl.txt – Mesut Nov 29 '09 at 06:17
The "ask for the name of the input file" part is the troublesome one. Not knowing anything about how that exe is coded, as I already mentioned, `wexpect` is the likeliest solution, as it lets you simulate exactly what that exe file would see when invoked at a cmd window. – Alex Martelli Nov 29 '09 at 06:23

score 45 · Answer 2 · edited Jun 03 '18 at 15:31

If using Python 2.7 or higher (especially prior to Python 3.5) you can use the following:

import subprocess

subprocess.call(args, *, stdin=None, stdout=None, stderr=None, shell=False) Runs the command described by args. Waits for command to complete, then returns the returncode attribute.
subprocess.check_call(args, *, stdin=None, stdout=None, stderr=None, shell=False) Runs command with arguments. Waits for command to complete. If the return code was zero then returns, otherwise raises CalledProcessError. The CalledProcessError object will have the return code in the returncode attribute

Example: subprocess.check_call([r"C:\pathToYourProgram\yourProgram.exe", "your", "arguments", "comma", "separated"])

In regular Python strings, the \U character combination signals a extended Unicode code point escape.

Here is the link to the documentation: http://docs.python.org/3.2/library/subprocess.html

For Python 3.5+ you can now use run() in many cases: https://docs.python.org/3.5/library/subprocess.html#subprocess.run

Python 3.6.3 recommends [run()](https://docs.python.org/3.6/library/subprocess.html#subprocess.run) — Ricardo Zorio, Nov 07 '17 at 22:48

score 39 · Answer 3 · edited Jun 03 '18 at 15:23

39

The simplest way is:

import os
os.startfile("C:\Documents and Settings\flow_model\flow.exe")

It works; I tried it.

edited Jun 03 '18 at 15:23

Peter Mortensen

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answered May 01 '12 at 08:17

Someone

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working properly, but is there a way to add parameters like -start and so on? – Bassem Shahin May 28 '18 at 15:29
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Doesn't work: `module 'os' has no attribute 'startfile'`. (Using python3.6) – not2qubit Nov 03 '18 at 01:04
Apparently doesn't work on anything Windows related, contrary to impression that the [documentation](https://docs.python.org/3.6/library/os.html#os.startfile) gives. – not2qubit Nov 03 '18 at 01:23

score 24 · Answer 4 · edited Jun 03 '18 at 15:16

24

I'd try inserting an 'r' in front of your path if I were you, to indicate that it's a raw string - and then you won't have to use forward slashes. For example:

os.system(r"C:\Documents and Settings\flow_model\flow.exe")

edited Jun 03 '18 at 15:16

Peter Mortensen

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answered Nov 28 '09 at 07:42

Jon Mills

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The main issue here are the spaces inside, your suggestion is fine but not addressing the main issue – Frediano Ziglio Jan 18 '21 at 16:33

score 21 · Answer 5 · edited Jun 03 '18 at 15:17

21

Your usage is correct. I bet that your external program, flow.exe, needs to be executed in its directory, because it accesses some external files stored there.

So you might try:

import sys, string, os, arcgisscripting
os.chdir('c:\\documents and settings\\flow_model')
os.system('"C:\\Documents and Settings\\flow_model\\flow.exe"')

(Beware of the double quotes inside the single quotes...)

edited Jun 03 '18 at 15:17

Peter Mortensen

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answered Nov 28 '09 at 09:08

Adrien Plisson

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Works perfectly, how would one store the results directly to a dataframe? – Sade Jun 25 '18 at 12:56

score 11 · Answer 6 · edited Oct 06 '14 at 12:33

11

Use subprocess, it is a smaller module so it runs the .exe quicker.

import subprocess
subprocess.Popen([r"U:\Year 8\kerbal space program\KSP.exe"])

edited Oct 06 '14 at 12:33

Robert

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answered Oct 06 '14 at 12:00

Frodo Baggins

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You mean it ***starts*** the `.exe` quicker? – Peter Mortensen Jun 03 '18 at 15:31

score 8 · Answer 7 · edited Oct 16 '14 at 21:08

8

By using os.system:

import os
os.system(r'"C:/Documents and Settings/flow_model/flow.exe"')

edited Oct 16 '14 at 21:08

Celeo

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answered Oct 16 '14 at 20:51

romy

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score 4 · Answer 8 · answered Nov 28 '09 at 05:39

4

Try

import subprocess
subprocess.call(["C:/Documents and Settings/flow_model/flow.exe"])

answered Nov 28 '09 at 05:39

int3

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tried it and the same thing happened. it seems like it opens the cmd window but then it wouldnt run the executable. I tried the executable separately and it works fine. I also moved the folder as C:/flow_model. Didnt make a difference.?? – Mesut Nov 28 '09 at 05:54

score 2 · Answer 9 · edited Jun 03 '18 at 15:20

If it were me, I'd put the EXE file in the root directory (C:) and see if it works like that. If so, it's probably the (already mentioned) spaces in the directory name. If not, it may be some environment variables.

Also, try to check you stderr (using an earlier answer by int3):

import subprocess
process = subprocess.Popen(["C:/Documents and Settings/flow_model/flow.exe"], \
                           stderr = subprocess.PIPE)
if process.stderr:
    print process.stderr.readlines()

The code might not be entirely correct as I usually don't use Popen or Windows, but should give the idea. It might well be that the error message is on the error stream.

score 2 · Answer 10 · answered Oct 15 '18 at 21:36

2

import os
path = "C:/Documents and Settings/flow_model/"
os.chdir(path)
os.system("flow.exe")

answered Oct 15 '18 at 21:36

John

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Please add an explanation of why your code solves this question. – rje Oct 15 '18 at 22:21
This post is basically treating the *.exe file being executed as you would using windows *.bat file. – SamAct Nov 08 '19 at 19:47

Bomba Ps · Answer 11 · 2019-05-09T11:18:37.917

in python 2.6 use string enclosed inside quotation " and apostrophe ' marks. Also a change single / to double //. Your working example will look like this:

import os
os.system("'C://Documents and Settings//flow_model//flow.exe'")

Also You can use any parameters if Your program ingest them.

os.system('C://"Program Files (x86)"//Maxima-gcl-5.37.3//gnuplot//bin//gnuplot -e "plot [-10:10] sin(x),atan(x),cos(atan(x)); pause mouse"')

finally You can use string variable, as an example is plotting using gnuplot directly from python:

this_program='C://"Program Files (x86)"//Maxima-gcl-5.37.3//gnuplot//bin//gnuplot'

this_par='-e "set polar; plot [-2*pi:2*pi] [-3:3] [-3:3] t*sin(t); pause -1"'
os.system(this_program+" "+this_par)

score 1 · Answer 12 · edited Jun 03 '18 at 15:15

1

Is that trying to execute C:\Documents with arguments of "and", "Settings/flow_model/flow.exe"?

Also, you might consider subprocess.call().

edited Jun 03 '18 at 15:15

Peter Mortensen

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answered Nov 28 '09 at 05:39

Thanatos

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score 0 · Answer 13 · answered Nov 28 '09 at 05:40

0

That's the correct usage, but perhaps the spaces in the path name are messing things up for some reason.

You may want to run the program under cmd.exe as well so you can see any output from flow.exe that might be indicating an error.

answered Nov 28 '09 at 05:40

Dan Olson

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score 0 · Answer 14 · edited Apr 26 '20 at 17:23

0

for the above question this solution works.

just change the path to where your executable file is located.

import sys, string, os

os.chdir('C:\\Downloads\\xpdf-tools-win-4.00\\xpdf-tools-win-4.00\\bin64')

os.system("C:\\Downloads\\xpdf-tools-win-4.00\\xpdf-tools-win-4.00\bin64\\flowwork.exe")


'''import sys, string, os

os.chdir('C:\\Downloads\\xpdf-tools-win-4.00\\xpdf-tools-win-4.00\\bin64')

os.system(r"C:\\Downloads\\xpdf-tools-win-4.00\\xpdf-tools-win-4.00\bin64\\pdftopng.exe test1.pdf rootimage")'''

Here test1.pdf rootimage is for my code .

edited Apr 26 '20 at 17:23

Greg Dubicki

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answered Aug 16 '18 at 05:34

spurthi

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Did you forget a closing `"` in `os.system`? – Suraj Rao Aug 16 '18 at 05:41

score 0 · Answer 15 · answered Nov 03 '18 at 02:53

There are loads of different solutions, and the results will strongly depend on:

the OS you are using: Windows, Cygwin, Linux, MacOS
the python version you are using: Python2 or Python3x

As I have discovered some things that are claimed to work only in Windows, doesn't, probably because I happen to use Cygwin which is outsmarting the OS way to deal with Windows paths. Other things only work in pure *nix based OS's or in Python2 or 3.

Here are my findings:

Generally speaking, os.system() is the most forgiving method.
os.startfile() is the least forgiving. (Windows only && if you're lucky)
subprocess.Popen([...]) not recommended
subprocess.run(winView, shell=True) the recommended way!
Remembering that using subprocess for anything may pose a security risk.

Try these:

import os, subprocess
...
winView = '/cygdrive/c/Windows/explorer.exe %s' % somefile
...
# chose one of these:
os.system(winView)
subprocess.Popen(['/cygdrive/c/Windows/explorer.exe', 'somefile.png'])
subprocess.run(winView, shell=True)

Q: Why would you want to use explorer in Windows?

A: Because if you just want to look at the results of some new file, explorer will automatically open the file with whatever default windows program you have set for that file type. So no need to re-specify the default program to use.

Running an outside program (executable) in Python?

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