For example, my String = 'xx22xx_1x_xxxx-xxxx', x can be any letters.
Now I want to delete the first two positions letters xx and seventh position 1, in order to get a NewString = '22xx_x_xxxx-xxxx'.
Any function to erase letters at specific positions?
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Shengen
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3this is trivial in python using slicing. what have you tried? – Mike Corcoran Jul 23 '13 at 20:29
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Maybe you could give us a more detailed description of your problem. There are several ways for achieving this, so it's a bit unclear what would be best in your case ... – Simon Steinberger Jul 23 '13 at 20:30
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1Strings are immutable, so you need to construct a *new* string. Use slicing. – Martijn Pieters Jul 23 '13 at 20:30
2 Answers
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You want to implement slicing! It is not just applicable to strings.
Example from this question: Is there a way to substring a string in Python?
>>> x = "Hello World!"
>>> x[2:]
'llo World!'
>>> x[:2]
'He'
>>> x[:-2]
'Hello Worl'
>>> x[-2:]
'd!'
>>> x[2:-2]
'llo Worl'
To Answer your question do this!
Removing the first two "xx"
NewString = String[2:]
Removing the 1
NewString = NewString[:5]+NewString[7:]
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Kirk Backus
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3
This will do it:
def erase(string, positions):
return "".join([y for x,y in enumerate(string) if x not in positions])
demo:
>>> s='xx22xx_1x_xxxx-xxxx'
>>> erase(s, (0,1,7))
'22xx_x_xxxx-xxxx'
>>>