How can i avoid ArrayIndexOutOfBoundsException in this case?

Question

Is it possible to avoid ArrayIndexOutOfBoundsException in this case ??

package com;

public class Hi {

    public static void main(String args[]) {

        String[] myFirstStringArray = new String[] { "String 1", "String 2",
                "String 3" };

        if (myFirstStringArray[3] != null) {
            System.out.println("Present");
        } else {
            System.out.println("Not Present");
        }

    }

}

it is always possible to avoid an ArrayIndexOutOfBoundsException, checking against `array.length` before accessing the array element — guido, Jul 18 '13 at 12:06
Your array will *always* have length 3, so index 3 is *always* invalid. It's not clear what you're asking really, but while you keep using an array of length three and asking for index 3, the answer is no: you can't avoid an exception. — Jon Skeet, Jul 18 '13 at 12:07
Are you from non-java background developer? its better to use exception handling... — Hariharan, Jul 18 '13 at 12:17

score 5 · Accepted Answer · answered Jul 18 '13 at 12:08

Maybe I don't understand the real problem, but what prevents you to check if the index is inside the array before accessing it in this case?

if (myIndex < myFirstStringArray.length) {
    System.out.println("Present");
} else {
    System.out.println("Not Present");
}

score 2 · Answer 2 · answered Jul 18 '13 at 12:07

In arrays, they are measured differently than numbers. The first object inside an array is considered 0. So, in your if statement, instead of a 3, you just put a 2.

if (myFirstStringArray[3] != null) {
        System.out.println("Present");

to

 if (myFirstStringArray[2] != null) {
        System.out.println("Present");

Hope this helps! :)

score 0 · Answer 3 · edited Jul 18 '13 at 13:08

0

Your String array contains 3 elements and you are accessing array[3] i.e. 4th element as index in 0 based and so you get this error (Exception, anyway).

To avoid the ArrayIndexOutOfBoundsException use an index within specified index range. And always check whether your index is >= array.length.

edited Jul 18 '13 at 13:08

zEro

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answered Jul 18 '13 at 12:07

Sachin Verma

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How can i avoid ArrayIndexOutOfBoundsException in this case?

3 Answers3