Program won't accept input for first search term

Question

I'm writing a program that includes a method to search for a song in an array of songs. Below is the code for this particular section that's giving me trouble. The kybd has already been initiated, and below is the code for the section, using the searchSong() method in my class.

    System.out.println("To search for a song, enter the following:");
    System.out.print("Title: ");
    searchT = kybd.nextLine();
    System.out.print("Author: ");
    searchAu = kybd.nextLine();
    System.out.print("Interpreter: ");
    searchI = kybd.nextLine();
    System.out.print("Album: ");
    searchAl = kybd.nextLine();
    System.out.println("Found this:"+'\n'+lib.searchSong(searchT, searchAl, searchAu, searchI));

When I run the program, it prints "Title" but doesn't let me enter the search term, it just skips straight to "Author." Below is the output I get.

To search for a song, enter the following:
Title: Author: search
Interpreter: search
Album: search

Can someone explain to me why this might be happening, and maybe how to fix it? I've checked and double checked my code and I can't figure it out.

Solved! I was using nextInt() for another method previously in the program. I took the advice in the question @Rohit Jain suggested and used a blank nextLine() before this section of code, and now it works. Thanks!

Can you show your complete code? It is not clear what you did before. — Rohit Jain, Jun 28 '13 at 18:09
possible duplicate of [Skipping nextLine() after use nextInt()](http://stackoverflow.com/questions/13102045/skipping-nextline-after-use-nextint) — Rohit Jain, Jun 28 '13 at 18:17
It seems like you have used `Scanner#nextInt()` somewhere before that code. Check the post above. It addresses the same issue. — Rohit Jain, Jun 28 '13 at 18:20
You're going to have to show how you initialize `kybd` or the code before the one you've posted. — Sotirios Delimanolis, Jun 28 '13 at 18:20
@RohitJain I have a feeling you're right or at least it's a similar problem... — Chris Thompson, Jun 28 '13 at 18:24
@ChrisThompson. Yeah, it's quite a general issue. Happens with beginners. — Rohit Jain, Jun 28 '13 at 18:25
@RohitJain You were right, I used nextInt previously in my program. Thanks! — alu, Jun 28 '13 at 18:28

sanbhat · Answer 1 · 2013-06-28T18:17:19.057

2

System.out.print("Title: "); should be replaced by System.out.println("Title: ");

I am assuming that

Scanner kybd = new Scanner(System.in);

since i see kybd.nextLine() method

Actually, the input is not getting skipped, just that Title: and Author: getting printed next to each other because of print instead of println. Did you try typing text and hitting enter? I am sure you will be allowed to type and enter text twice

edited Jun 28 '13 at 18:17

answered Jun 28 '13 at 18:09

sanbhat

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His problem is that his code is skipping the input. How does your fix change that? – Sotirios Delimanolis Jun 28 '13 at 18:14
_When I run the program, it prints "Title" but doesn't let me enter the search term, it just skips straight to "Author."_ – Sotirios Delimanolis Jun 28 '13 at 18:18
1

The problem is not about printing newline. It's about not reading input for one variable, and moving to another directly. – Rohit Jain Jun 28 '13 at 18:19
1

I've tried, and it does skip "Title" and my input gets assigned to "Author". – alu Jun 28 '13 at 18:19
@sanbhat I don't doubt it. It should work with `print()` as well. There's something OP isn't showing. Your answer is incorrect for handling OP's problem. `println()` over `print()` does nothing to prevent skipping input. – Sotirios Delimanolis Jun 28 '13 at 18:23
@sanbhat Was the `nextInt()` finally. – Sotirios Delimanolis Jun 28 '13 at 18:29

Program won't accept input for first search term

1 Answers1