Why id is not found when I access through tag?

Asked May 21 '13 at 13:03

Active May 21 '13 at 17:32

Viewed 1,840 times

2

 <h:panelGroup id="userPanel"><f:subview rendered="#{searchView.isUser}">
    <h:commandButton value="test" action="#{searchAction.doFindUsers}"   >
        <f:ajax execute="@this" event="action" render="userPanel" />
    </h:commandButton> </f:subview></h:panelGroup>

I am getting the error as: cannot locate it in the context of the component j_idt26

edited May 21 '13 at 17:28

BalusC

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asked May 21 '13 at 13:03

CSK

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1 Answers1

5

Because the <f:subview> is a NamingContainer.

See also:

How to find out client ID of component for ajax update/render? Cannot find component with expression "foo" referenced from "bar"

Just use <h:panelGroup>,

<h:panelGroup id="userPanel">
    <h:panelGroup rendered="#{searchView.isUser}">
        <h:commandButton value="test" action="#{searchAction.doFindUsers}">
            <f:ajax execute="@this" event="action" render="userPanel" />
        </h:commandButton>
    </h:panelGroup>
</h:panelGroup>

or <ui:fragment> (which has only a little less overhead)

<h:panelGroup id="userPanel">
    <ui:fragment rendered="#{searchView.isUser}">
        <h:commandButton value="test" action="#{searchAction.doFindUsers}">
            <f:ajax execute="@this" event="action" render="userPanel" />
        </h:commandButton>
    </ui:fragment>
</h:panelGroup>

or in this specific example just directly on command button (surely your case is more complex than that)

<h:panelGroup id="userPanel">
    <h:commandButton value="test" action="#{searchAction.doFindUsers}"  rendered="#{searchView.isUser}">
        <f:ajax execute="@this" event="action" render="userPanel" />
    </h:commandButton>
</h:panelGroup>

See also:

edited May 23 '17 at 12:08

Community

1
1

answered May 21 '13 at 17:32

BalusC

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